我正在尝试编写一个小型解析器。不幸的是,我遇到了“减少班次冲突”。语法不是我的强项,我只需要完成这件小事。这是产生错误的简化语法:
stmts_opt -> stmts
;
stmts -> stmt
| stmts stmt
| stmsts
;
stmt -> id
| ITERATE content_stmt
| IF test then content_stmt ELSE content_stmt
| IF test then content_stmt
;
content_stmt: BEGIN stmt_opt END
| stmt
;
提供修改后的语法的解决方案将受到高度赞赏。
编辑:
我修改了适合@rici 答案的语法,但问题仍然存在。这是我的实际语法制作:
prog: BEGIN_PROG def_sprogram BEGIN_EXEC stmts_opt END_EXEC END_PROG
{ () }
;
def_sprogram: /* empty */ { () }
| define_new def_sprogram { () }
;
define_new: DEFINE_NEW_INSTRUCTION ID AS content_stmt SEMI { }
;
stmts_opt: /* empty */ { () }
| stmts { () }
;
stmts: stmt { () }
| stmts SEMI stmt { () }
| stmts SEMI { () }
;
content_stmt: BEGIN stmts_opt END { () }
| stmt { () }
;
stmt: open_stmt { () }
| closed_stmt { () }
;
open_stmt: ITERATE INT TIMES open_stmt { () }
| WHILE test DO open_stmt { () }
| IF test THEN closed_stmt ELSE open_stmt { () }
| IF test THEN stmt { () }
;
closed_stmt: simple_stmt { () }
| ITERATE INT TIMES closed_stmt { () }
| WHILE test DO closed_stmt { () }
| IF test THEN closed_stmt ELSE closed_stmt { () }
;
这是我正在测试的示例:
BEGINNING-OF-PROGRAM
BEGINNING-OF-EXECUTION
IF not-next-to-a-beeper THEN
move;
IF not-facing-north THEN
turnleft;
ELSE <--- ERROR
turnleft;
IF not-facing-east THEN
IF not-facing-west THEN
turnleft;
turnoff
END-OF-EXECUTION
END-OF-PROGRAM
我在第一个中遇到错误ELSE
。我还尝试按照@rici 的建议声明一个简单的优先级:
%nonassoc THEN
%nonassoc ELSE
但这也没有解决错误。