1

我有我的简单注射器注册:

container.RegisterConditional(typeof(ILogManager),
c => typeof(LogManager<>).MakeGenericType(c.Consumer.ImplementationType),
Lifestyle.Singleton,
c => true);

我需要使用 Castle Windsor 在不同的项目中注册相同的 LogManager。

我努力了

container.Register(Component.For(typeof(ILogger))
            .ImplementedBy(typeof(Log4NetLogger<>).MakeGenericType())
            .LifeStyle.Singleton.Start());

不能让它工作。

4

1 回答 1

2

不幸的是,这对于 Castle 来说更加复杂。但是您可以使用 SubDependencyResolver 获得相同的结果:

public class LoggerResolver : ISubDependencyResolver
{
    public bool CanResolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        return dependency.TargetType == typeof(ILogger);
    }

    public object Resolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        var logger = typeof(LogManager<>).MakeGenericType(model.Implementation);
        return Activator.CreateInstance(logger);
    }
}

而不是将其添加到内核中:

Kernel.Resolver.AddSubResolver(new LoggerResolver())

另一种方法是使用 GenericImplementationMatchingStrategy。如果 LogManager 有一些依赖项,这个也可以工作:

public class OpenGenericAncestorMatchingStrategy : IGenericImplementationMatchingStrategy
{
    public Type[] GetGenericArguments(ComponentModel model, CreationContext context)
    {
        return new[] { context.Handler.ComponentModel.Implementation };
    }
}

和注册:

container.Register(Component.For<ILogger>().ImplementedBy(typeof(LogManager<>), new OpenGenericAncestorMatchingStrategy()));
于 2017-09-21T14:09:42.453 回答