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我正在尝试使用内置的 PHP 邮件功能来发送包含我的消息的 html 和纯文本版本的多部分消息。我一直在玩不同的编码类型，但是我一直遇到问题。最初我设置Content-Transfer-Encoding为Binary但是，这导致每 78 个字符放置一个感叹号。我也尝试过base64，但我相信 base64 对我正在做的事情来说太过分了。

我所做的只是发送基本的 HTML，没有编码的图像、文件或附件。我更喜欢一种仍然允许源代码可读的编码方法。

我听说这Quoted-Printable就是我正在寻找的东西，但是，当我尝试使用该编码类型发送消息时，结果看起来真的很奇怪。"我注意到消息源代码中散布着一堆符号。

这是我正在使用的代码： 

    $to = "to@test.com";
    $subject = "test subject";
    $boundary = uniqid('np');               
    $headers = "MIME-Version: 1.0\r\n";
    $headers .= "From: from-address@test.com\r\n";
    $headers .= "Reply-To: reply-address@test.com\r\n";
    $headers .= "Return-Path: return-path@test.com\r\n";
    $headers .= "Content-Type: multipart/alternative;boundary=" . $boundary . "\r\n";
    $message = "This is a MIME encoded message.";

    $message .= "\r\n\r\n--" . $boundary . "\r\n";
    $message .= "Content-Type: text/plain; charset=UTF-8\r\n";
    $message .= "Content-Transfer-Encoding: Quoted-Printable\r\n";
    $message .= $plainTextMessage;

    $message .= "\r\n\r\n--" . $boundary . "\r\n";
    $message .= "Content-Type: text/html; charset=UTF-8\r\n";
    $message .= "Content-Transfer-Encoding: Quoted-Printable\r\n";
    $message .= $HTMLmessage;

    $message .= "\r\n\r\n--" . $boundary . "--";

    $ok = mail($to,$subject,$message,$headers);

我到底做错了什么？

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2 回答 2

0

嗨试试下面的代码，

    $to = "to@test.com";
    $subject = "test subject";
    $plainTextMessage = "Hi all";
    $HTMLmessage = "<b>Hi all</b>";
     //$boundary = uniqid('np');               
    $boundary = md5(uniqid(time()));   
    $headers .= "From: from-address@test.com\r\n";
    $headers .= "Reply-To: reply-address@test.com\r\n";
    $headers .= "Return-Path: return-path@test.com\r\n";
    $headers .= "Content-Type: multipart/alternative;boundary=" . $boundary . "\r\n";
    $message = "This is a MIME encoded message.";

    $message .= "\r\n\r\n--" . $boundary . "\r\n";
    $message .= "Content-Type: text/plain; charset=UTF-8\r\n";
    $message .= "Content-Transfer-Encoding: Quoted-Printable\r\n";
    $message .= $plainTextMessage;

    $message .= "\r\n\r\n--" . $boundary . "\r\n";
    $message .= "Content-Type: text/html; charset=UTF-8\r\n";
    $message .= "Content-Transfer-Encoding: Quoted-Printable\r\n";
    $message .= $HTMLmessage;

    $message .= "\r\n\r\n--" . $boundary . "--";

    $ok = mail($to,$subject,$message,$headers);

可能会有所帮助

于 2017-09-08T12:19:46.727 回答
0

无需第三方库或外部邮件转发主机。这就是我使用的，它就像一个魅力。它还通过强制标头使用$from地址来修复一些潜在的安全漏洞，否则可能会泄露您的系统用户：

private function sendMail($to, $from, $fromName, $subject, $text, $html)
{

    $boundary = uniqid('np');

    $headers = "MIME-Version: 1.0\r\n";
    $headers .= "From: ".$fromName." <".$from.">" . "\r\n"; 
    $headers .= "X-Sender: ".$fromName." <".$from.">\n";
    $headers .= "Return-Path: <".$from.">\n";
    $headers .= "To: ".$to."\r\n";
    $headers .= "Content-Type: multipart/alternative;boundary=" . $boundary . "\r\n";

    // Content body
    $message = "This is a MIME encoded message.";
    $message .= "\r\n\r\n--" . $boundary . "\r\n";
    $message .= "Content-type: text/plain;charset=utf-8\r\n\r\n";

    // Plain text body
    $message .= $text;
    $message .= "\r\n\r\n--" . $boundary . "\r\n";
    $message .= "Content-type: text/html;charset=utf-8\r\n\r\n";

    // Html body
    $message .= $html;
    $message .= "\r\n\r\n--" . $boundary . "--";

    // Send mail
    mail('', $subject, $message, $headers, '-f ' . $from);

}
于 2019-12-21T07:15:31.780 回答