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我已经完全按照 Google 教程中提到的那样创建和设置了 Firebase 控制台。我也在我的项目中实现了服务。当我从 Firebase 控制台发送消息时，它没有在我的应用程序中接收。当我尝试使用单个设备发送时，它显示“未注册的注册令牌”。

这是我的 MyFirebaseInstanceIDService：

public class MyFirebaseInstanceIDService extends FirebaseInstanceIdService {

    @Override
    public void onTokenRefresh() {

        //Getting registration token
        String refreshedToken = FirebaseInstanceId.getInstance().getToken();
        System.out.println("TOKEN::" + refreshedToken);
        //Displaying token on logcat

        SmartApplication.REF_SMART_APPLICATION.writeSharedPreferences("regId", refreshedToken);
//        SharedPreferences pref = getApplicationContext().getSharedPreferences(Config.SHARED_PREF, 0);
//        SharedPreferences.Editor editor = pref.edit();
//        editor.putString("regId", refreshedToken);
//        editor.commit();
    }
}

这是我的 MyFirebaseMessagingService：

public class MyFirebaseMessagingService extends FirebaseMessagingService {

    private static final String TAG = "MyFirebaseMsgService";
    private static int count = 0;
    String TYPE = "type";

    @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        //Displaying data in log
        //It is optional
        System.out.println("data getting");
        Log.d(TAG, "Notification Message TITLE: " + remoteMessage.getNotification().getTitle());
        Log.d(TAG, "Notification Message BODY: " + remoteMessage.getNotification().getBody());
        Log.d(TAG, "Notification Message DATA: " + remoteMessage.getData().toString());

        //Calling method to generate notification
        //remoteMessage.getNotification().getBody()
        sendNotification(remoteMessage.getNotification().getTitle(),
                remoteMessage.getNotification().getBody(), remoteMessage.getData());
    }


    //This method is only generating push notification
    //It is same as we did in earlier posts
    private void sendNotification(String messageTitle, String messageBody, Map<String, String> row) {
        PendingIntent contentIntent = null;
        try {
            Intent groupDetailIntent = new Intent(this, UnanimousHomeActivity.class);

            contentIntent = PendingIntent.getActivity(this, (int) (Math.random() * 100),
                    groupDetailIntent, PendingIntent.FLAG_UPDATE_CURRENT);
        } catch (Exception e) {
            e.printStackTrace();
        }
        Uri defaultSoundUri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
                .setSmallIcon(R.mipmap.ic_launcher)
                .setContentTitle(messageTitle)
                .setContentText(messageBody)
                .setAutoCancel(true)
                .setSound(defaultSoundUri)
                .setContentIntent(contentIntent);

        NotificationManager notificationManager =
                (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        notificationManager.notify(count, notificationBuilder.build());
        count++;
    }
}

我已经卡住了 4 天，请有人帮助我，因为这里没有发现逻辑问题，集成推送时发生了一些不寻常的事情。

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3 回答 3

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成功获取令牌后，请确保已将其正确发送到服务器。

尝试针对无效注册令牌的推荐操作：

检查您传递给服务器的注册令牌的格式。确保它与客户端应用通过 Firebase 通知注册收到的注册令牌相匹配。不要截断或添加其他字符。

有关详细信息，请参阅此文档。

于 2017-09-02T11:47:48.797 回答
0 
public class MyFirebaseMessagingService extends FirebaseMessagingService {

    private static final String TAG = MyFirebaseMessagingService.class.getSimpleName();

    @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        Log.e(TAG, "From: " + remoteMessage.getFrom());


        // Check if message contains a data payload.
        if (remoteMessage.getData().size() > 0) {
            Log.e(TAG, "Message data: " + remoteMessage.getData().toString());



        }

        if (remoteMessage.getNotification() != null) {
            Log.e(TAG, "Message data: " + remoteMessage.getData().toString());
            sendnotification(remoteMessage.getNotification().getBody());



        }
    }

    private void sendnotification(String body) {

        Intent intent = new Intent(this,MainActivity.class);
        intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);

        PendingIntent pendingIntent = PendingIntent.getActivity(this,0,intent,PendingIntent.FLAG_ONE_SHOT);

        Uri notificationsound = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);

        NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
                .setSmallIcon(R.mipmap.ic_launcher)
                .setContentTitle("Emoji Keyboard")
                .setDefaults(-1)
                .setContentText(body)
                .setVibrate(new long[] { 1000, 1000, 1000, 1000, 1000 })
                .setSound(notificationsound)
                .setAutoCancel(true)
                .setContentIntent(pendingIntent);

        NotificationManager notificationManager = (NotificationManager)getSystemService(Context.NOTIFICATION_SERVICE);
        notificationManager.notify(0,notificationBuilder.build());
    }


}

and after this in manifests add this:

 <!-- Firebase Notifications -->
        <service android:name=".services.MyFirebaseMessagingService">
            <intent-filter>
                <action android:name="com.google.firebase.MESSAGING_EVENT" />
            </intent-filter>
        </service>

        <service android:name=".services.MyFirebaseInstanceIDService">
            <intent-filter>
                <action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
            </intent-filter>
        </service>
        <!-- ./Firebase Notifications -->
于 2017-09-01T12:24:30.367 回答
0

代码在我的应用程序中运行良好

在从 firebase 创建的 app 文件夹中添加 googleservices-json 文件并在清单中添加服务

<service
            android:name=".MyFirebaseMessagingService">
            <intent-filter>
                <action android:name="com.google.firebase.MESSAGING_EVENT"/>
            </intent-filter>
        </service>
        <service
            android:name=".MyFirebaseInstanceIDService">
            <intent-filter>
                <action android:name="com.google.firebase.INSTANCE_ID_EVENT"/>
            </intent-filter>
        </service>
于 2017-09-06T12:20:14.427 回答