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使用 swift 类在 MathParser swift 框架和 Objective-c 项目之间架起桥梁，@objc public func evaluateString(string: String, substitutions:Substitutions = [:]) throws -> NSNumber使用 Swift 3 编译没有问题，但 Swift 4 不会接受它。

尝试声明 as @objc public func evaluateString(string: String, substitutions: Dictionary<String, Any> = [:]) throws -> NSNumber，它编译但是运行时错误指示 EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subcode=0x0) 在尝试向下转换时substitutions。

MathParser 可以在https://github.com/davedelong/DDMathParser/tree/master/MathParser找到。欣赏这里的任何方向，因为 swift 有点笨拙。

import Foundation
import MathParser

@objc public enum AngleMode : Int {
    case Radians
    case Degrees
}

@objc public class DDMathParser : NSObject
{
    @objc public var angleMeasurementMode = AngleMode.Radians
    @objc public var Error : NSError?

//    @objc public func evaluateString(string: String, substitutions: Dictionary<String, Any> = [:]) throws -> NSNumber
    @objc public func evaluateString(string: String, substitutions:Substitutions = [:]) throws -> NSNumber
    {
        do {
            let evaluator = Evaluator()
            let expression = try Expression(string: string as String)
//                let bridgedSubstitutions = substitutions as? Substitutions
            let value = try evaluator.evaluate(expression, substitutions: substitutions!)
            return NSNumber .init(value: value);
        } catch let error as MathParserError {

…………

    public protocol Substitution {
        func substitutionValue(using evaluator: Evaluator, substitutions: Substitutions) throws -> Double
        func substitutionValue(using evaluator: Evaluator) throws -> Double

        func simplified(using evaluator: Evaluator, substitutions: Substitutions) -> Substitution
        func simplified(using evaluator: Evaluator) -> Substitution
    }

    public extension Substitution {
        func substitutionValue(using evaluator: Evaluator) throws -> Double {
            return try substitutionValue(using: evaluator, substitutions: [:])
        }

        func simplified(using evaluator: Evaluator) -> Substitution {
            return simplified(using: evaluator, substitutions: [:])
        }
    }

    public typealias Substitutions = Dictionary<String, Substitution>
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