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我将在4 × 6(代码中的 m×n)矩阵的每个单元格上使用以下公式来获得归一化矩阵:
\pi_{ij}=\frac{x_{ij}}{\sqrt{\Sigma_{i=1}^m x_{ij}^2}}

Calc 中的矩阵为:
在此处输入图像描述

我在 LibreOffice 中使用以下基本代码:

REM  *****  BASIC  *****

Sub Main

Normalize(5,3)

End Sub



Sub Normalize (ByVal n As Integer,ByVal m As Integer)

Dim Doc As Object
Dim Sheet As Object
Dim SrcCell 'Cell in the source matrix 
Dim TargetCell 'Cell in the target matrix where normalized values are saved 
Dim TempCell As Object 

Dim I 'index 
Dim J 'index 
Dim JJ 'inner index 
Dim Sum 'Sigma x_ij^2 (j=0 to m)
Dim m 'maximum row index 
Dim n 'maximum column index 


Doc = ThisComponent
Sheet = Doc.Sheets(0)




For I = 0 to n  'traverse columns 
    For J=0 to m 'traverse rows 
        SrcCell = Sheet.getCellByPosition(I,J)
        'Now apply the normalization formula for this cell 
        'Run a new loop to run formula on this cell 
        Sum = 0 'Reset Sum to 0
        For JJ=0 to m 
            TempCell = Sheet.getCellByPosition(I,JJ)
            Sum = Sum + (TempCell.Value^2)
        Next 
        TargetCell = Sheet.getCellByPosition(I+n+1,J) 'Place the normalized cells in a new matrix cell, n+1 cells away

        'Put the sum in the formula 
        TargetCell.Value = SrcCell.Value/Sqr(Sum)

    Next 


Next 

End Sub 

我想让归一化矩阵出现在原始矩阵的右侧。但什么也没有出现。我究竟做错了什么?

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1 回答 1

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代码使用nandm作为参数,但随后声明它们,破坏值。要修复,请删除以下两行。为了便于阅读,请将这些注释移到Sub Normalize.

Dim m 'maximum row index 
Dim n 'maximum column index

要使用 Basic IDE 调试器查找此类问题,请按工具栏中的 Breakpoint On/Off 设置几个断点,并启用 Watch。

于 2017-07-07T09:48:54.230 回答