3

单击按钮后，我想使 qtooltip 消息持久化。我打算稍后使用 qtimer 自己隐藏它，但问题是一旦我将鼠标光标从按钮 rect 移开，消息就会消失，我想让它留在那里，直到稍后我打电话hideText()

from PyQt4 import QtGui, QtCore
from functools import partial

class MyDialog(QtGui.QDialog):

    def __init__(self, parent=None):
        super(MyDialog, self).__init__(parent)
        layout = QtGui.QVBoxLayout()
        btn = QtGui.QPushButton('Push Me')
        layout.addWidget(btn)
        self.setLayout(layout)

        btn.clicked.connect(partial(self.showFloatingMessage,'This is a long message'))

    def showFloatingMessage(self, message='', delay=500):

        desktop = QtGui.QApplication.desktop()
        screen_num = desktop.screenNumber(QtGui.QCursor.pos())
        screen_rect = desktop.screenGeometry(screen_num)
        QtGui.QToolTip.showText(screen_rect.center(), message, None, screen_rect)


app = QtGui.QApplication([])

dialog = MyDialog()
dialog.show()

app.exec_()
4

1 回答 1

1

一个可能的解决方案是使用 QLabel 作为 QToolTip，我们通过启用 Qt.ToolTip 标志来做到这一点。在你的情况下：

from PyQt4 import QtGui, QtCore


class MyDialog(QtGui.QDialog):

    def __init__(self, parent=None):
        super(MyDialog, self).__init__(parent)
        layout = QtGui.QVBoxLayout()
        btn = QtGui.QPushButton('Push Me')
        layout.addWidget(btn)
        self.setLayout(layout)

        btn.clicked.connect(lambda: self.showFloatingMessage('This is a long message', 5000))

    def showFloatingMessage(self, message='', delay=500):
        desktop = QtGui.QApplication.desktop()
        screen_num = desktop.screenNumber(QtGui.QCursor.pos())
        screen_rect = desktop.screenGeometry(screen_num)

        lb = QtGui.QLabel(self)
        lb.setWindowFlags(QtCore.Qt.ToolTip)
        lb.setText(message)
        lb.move(screen_rect.center())
        lb.show()
        QtCore.QTimer.singleShot(delay, lb.hide)


app = QtGui.QApplication([])

dialog = MyDialog()
dialog.show()

app.exec_()
于 2017-06-09T20:46:07.763 回答