5

我正在开发一个面向群体的网络应用程序。问题是当我要加入一个组时,它首先检查该组是否安全,如果是,它会询问用户名和密码。获得组安全性可能需要几秒钟,所以我为整个过程生成了一个新线程。如果该组需要安全性,我想弹出一个对话框。我认为这可能与后台线程有关,它们可能无法弹出对话框......但问题是我需要检查后台线程中的组安全性,因为这需要一些时间。

希望任何人都可以提出解决方案或仅在组安全时询问用户/通过的任何方式。这是后台线程:

public void run() {

 secInf = mGroupId.getSecurityInformation();
 if (secInf.getAdmissionLevel() == CreateGroupDialog.PRIVATE_KEY_ACCESS) {
  showUserPasswordDialog();
 } else {
  mService.joinGroup(mGroupId);
  // Notifies handler to dismiss ProgresDialog and start activity
  mHandler.sendMessage(Message.obtain(mHandler,
      GroupsActivity.JOIN_SUCCESSFUL));
 }

showUserPasswordDialog 的作用(mActivity 是产生此线程的活动):

 private void showUserPasswordDialog() {
  AlertDialog dialog;
  // add this to your code
  // This example shows how to add a custom layout to an AlertDialog
  LayoutInflater factory = LayoutInflater.from(mActivity);
  final View textEntryView = factory.inflate(
    R.layout.alert_dialog_text_entry, null);

  AlertDialog.Builder builder = new AlertDialog.Builder(mActivity);
  builder.setIcon(R.drawable.alert_dialog_icon);
  builder.setTitle(R.string.ask_user_password);
  builder.setView(textEntryView);
  builder.setPositiveButton(R.string.ok_text,
    new DialogInterface.OnClickListener() {
     public void onClick(DialogInterface dialog, int whichButton) {
      String userName = ((EditText) mActivity
        .findViewById(R.id.username_edit_alert_dialog))
        .getText().toString();
      String password = ((EditText) mActivity
        .findViewById(R.id.password_edit_alert_dialog))
        .getText().toString();
      Credentials cred = new CredentialsL1(userName, password);

      mSmeppService.joinGroup(mGroupId, cred);

      mHandler.sendMessage(Message.obtain(mHandler,
        GroupsActivity.JOIN_SUCCESSFUL));
    });
  builder.setNegativeButton(R.string.cancel_text,
    new DialogInterface.OnClickListener() {
     public void onClick(DialogInterface dialog, int whichButton) {
      dialog.cancel();
      mHandler.sendMessage(Message.obtain(mHandler,
        GroupsActivity.DISMISS_PROGRESS_DIALOG));
     }
    });

  dialog = builder.create();

  /* I found this somewhere, but didn't work either */
  // Window window = dialog.getWindow();
  // WindowManager.LayoutParams lp = window.getAttributes();
  // lp.token = textEntryView.getWindowToken();
  // lp.type = WindowManager.LayoutParams.TYPE_APPLICATION_ATTACHED_DIALOG;
  // window.setAttributes(lp);
  // window.addFlags(WindowManager.LayoutParams.FLAG_ALT_FOCUSABLE_IM);

  dialog.show();

 }

我得到了这个例外:

12-13 19:18:31.823: ERROR/AndroidRuntime(1702): FATAL EXCEPTION: Thread-38
12-13 19:18:31.823: ERROR/AndroidRuntime(1702): android.view.InflateException: Binary XML file line #17: Error inflating class android.widget.EditText
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.view.LayoutInflater.createView(LayoutInflater.java:513)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at com.android.internal.policy.impl.PhoneLayoutInflater.onCreateView(PhoneLayoutInflater.java:56)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.view.LayoutInflater.createViewFromTag(LayoutInflater.java:563)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.view.LayoutInflater.rInflate(LayoutInflater.java:618)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.view.LayoutInflater.inflate(LayoutInflater.java:407)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.view.LayoutInflater.inflate(LayoutInflater.java:320)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.view.LayoutInflater.inflate(LayoutInflater.java:276)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at org.pfc.threads.GroupJoinerThread.showUserPasswordDialog(GroupJoinerThread.java:76)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at org.pfc.threads.GroupJoinerThread.run(GroupJoinerThread.java:52)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702): Caused by: java.lang.reflect.InvocationTargetException
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.widget.EditText.<init>(EditText.java:51)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at java.lang.reflect.Constructor.constructNative(Native Method)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at java.lang.reflect.Constructor.newInstance(Constructor.java:446)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.view.LayoutInflater.createView(LayoutInflater.java:500)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     ... 8 more
12-13 19:18:31.823: ERROR/AndroidRuntime(1702): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.os.Handler.<init>(Handler.java:121)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.text.method.MetaKeyKeyListener$MetaKeyDropbackHandler.<init>(MetaKeyKeyListener.java:605)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.text.method.MetaKeyKeyListener.<init>(MetaKeyKeyListener.java:96)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.text.method.BaseKeyListener.<init>(BaseKeyListener.java:25)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.text.method.TextKeyListener.<init>(TextKeyListener.java:66)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.text.method.TextKeyListener.getInstance(TextKeyListener.java:83)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.widget.TextView.<init>(TextView.java:806)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     at android.widget.EditText.<init>(EditText.java:55)
12-13 19:18:31.823: ERROR/AndroidRuntime(1702):     ... 12 more

XML 布局文件为:

   <EditText
       android:id="@+id/username_edit_alert_dialog"
       android:enabled="false"
       android:layout_height="wrap_content"
       android:layout_width="fill_parent"
       android:layout_marginLeft="20dip"
       android:layout_marginRight="20dip"
       android:scrollHorizontally="true"
       android:autoText="false"
       android:capitalize="none"
       android:gravity="fill_horizontal"
       android:textAppearance="?android:attr/textAppearanceMedium" />
  <!-- Password -->
   <TextView
       android:id="@+id/password_view"
       android:layout_height="wrap_content"
       android:layout_width="wrap_content"
       android:layout_marginLeft="20dip"
       android:layout_marginRight="20dip"
       android:text="@string/password_view_text"
       android:gravity="left"
       android:textAppearance="?android:attr/textAppearanceMedium" />

   <EditText
       android:id="@+id/password_edit_alert_dialog"
       android:enabled="false"
       android:layout_height="wrap_content"
       android:layout_width="fill_parent"
       android:layout_marginLeft="20dip"
       android:layout_marginRight="20dip"
       android:scrollHorizontally="true"
       android:autoText="false"
       android:capitalize="none"
       android:gravity="fill_horizontal"
       android:password="true"
       android:textAppearance="?android:attr/textAppearanceMedium" />

4

3 回答 3

6

您是正确的,您不能从后台线程执行 UI 操作。这样做的方法是使用Handler您已经实现的弹出对话框。所以像:

private Handler handler = new Handler(){
    @Override
    public void handleMessage(Message msg) {
        switch(msg.what){
        case GroupsActivity.DISMISS_PROGRESS_DIALOG:
            //your existing dismiss code
            break;
        case GroupsActivity.CREATE_PROGRESS_DIALOG:
            //create the dialog
            break;
        }
    }
};

那么你的运行方法将是:

public void run() {

    secInf = mGroupId.getSecurityInformation();
    if (secInf.getAdmissionLevel() == CreateGroupDialog.PRIVATE_KEY_ACCESS) {
        // do stuff
        mHandler.sendMessage(Message.obtain(mHandler,
            GroupsActivity.CREATE_PROGRESS_DIALOG));
        // do more stuff
    } else {
        mService.joinGroup(mGroupId);
        // Notifies handler to dismiss ProgresDialog and start activity
        mHandler.sendMessage(Message.obtain(mHandler,
            GroupsActivity.JOIN_SUCCESSFUL));
    }
}
于 2010-12-13T19:14:42.110 回答
2

你是对的。后台线程无法弹出对话框。您需要的是Handler在您的 UI 线程上为您弹出对话框。

于 2010-12-13T19:11:44.133 回答
0

虽然这样做不是一个好主意,而且这个答案只是为了完整起见,但显示对话框形式的非 UI 线程是可能的。

handlerThread = HandlerThread("myHandlerThread")
handlerThread?.start()
handler1 = Handler(handlerThread?.looper)

handler1?.post {
    AlertDialog
        .Builder(this)
        .setPositiveButton("ok") { dialogInterface: DialogInterface, i: Int -> dialogInterface.dismiss() }
        .create()
        .show()
}
于 2018-10-11T11:14:12.417 回答