python - 给定一个邻接矩阵，如何用 matplotlib 绘制图形？

Question

我有一个由它的邻接矩阵（一个numpy数组）描述的无向图，我想绘制它，顶点放置在一个正多边形中。此代码有效：

n = adyacency_mathix.shape[0]
axis = np.linspace(0, 2*np.pi, n, endpoint=False)
x, y = np.cos(axis), np.sin(axis)
for i in xrange(n):
    for j in xrange(i + 1, n):
        if self.matrix[i, j] == 1:
            pyplot.plot((x[i], x[j]), (y[i], y[j]), color = 'blue')
pyplot.show()

但可以优化。

Answer 1

networkx如果您只想减少编写的代码量，您可能对流行的项目感兴趣。

import matplotlib.pyplot as plt
import networkx as nx

# Generating sample data
G = nx.florentine_families_graph()
adjacency_matrix = nx.adjacency_matrix(G)

# The actual work
# You may prefer `nx.from_numpy_matrix`.
G2 = nx.from_scipy_sparse_matrix(adjacency_matrix)
nx.draw_circular(G2)
plt.axis('equal')

免责声明：我是networkx.