0

我试图破译如何在 zend-mvc 的最新版本下正确混合 ZF3 中间件之间的变量。

想象一下这样的路线:

'sandwich-test' => [
    'type' => \Zend\Router\Http\Literal::class,
    'options' => [
        'route' => '/events/sandwich',
        'defaults' => [
            'middleware' => [
                \Foo\Middleware\JsonWrappingMiddleware::class,
                \Foo\Middleware\TestMiddleware::class,
            ],
        ],
    ],
],

在我的简单测试中,我希望 JsonWrappingMiddleware 简单地返回 JsonResponse,即 TestMiddleware 返回的变量。

单独来说,这有效:

use Interop\Http\ServerMiddleware\DelegateInterface;
use Interop\Http\ServerMiddleware\MiddlewareInterface;
use Psr\Http\Message\ServerRequestInterface;
use Zend\Diactoros\Response\JsonResponse;

class JsonWrappingMiddleware implements MiddlewareInterface
{
    public function process(ServerRequestInterface $request, DelegateInterface $delegate)
    {

        return new JsonResponse(['c' => 'd']);
    }
}

...和...

use Interop\Http\ServerMiddleware\DelegateInterface;
use Interop\Http\ServerMiddleware\MiddlewareInterface;
use Psr\Http\Message\ServerRequestInterface;
use Zend\Diactoros\Response\JsonResponse;

class TestMiddleware implements MiddlewareInterface
{
    public function process(ServerRequestInterface $request, DelegateInterface $delegate)
    {
        return new JsonResponse(['a' => 'b']);
    }
}

但接下来,如何让他们一起努力回归

[ 'a' => 'b', 'c' => 'd', ]
4

1 回答 1

0

您发送响应两次,如果您希望中间件传递一些数据然后使用$request->withAttribute($name, $value): RequestInterface,然后在第二个(或只是最后一个)中间件获取该数据并将其转换为正确的JsonResponse

于 2017-05-26T08:40:58.017 回答