7

我在 MSSQL2005 中有下表

id | business_key | result
1 | 1 | 0
2 | 1 | 1
3 | 2 | 1
4 | 3 | 1
5 | 4 | 1
6 | 4 | 0

现在我想根据返回具有最高 id 的完整条目的 business_key 进行分组。所以我的预期结果是：

business_key | result
1 | 1
2 | 1
3 | 1
4 | 0

我敢打赌，有一种方法可以实现这一点，我现在看不到它。

4

5 回答 5

15

另一种解决方案，它可以为您提供更好的性能（测试两种​​方式并检查执行计划）：

SELECT
     T1.id,
     T1.business_key,
     T1.result
FROM
     dbo.My_Table T1
LEFT OUTER JOIN dbo.My_Table T2 ON
     T2.business_key = T1.business_key AND
     T2.id > T1.id
WHERE
     T2.id IS NULL

此查询假定 ID 是唯一值（至少对于任何给定的 business_key）并且它设置为 NOT NULL。

于 2009-01-13T13:46:30.573 回答
5 
select
  drv.business_key,
  mytable.result
from mytable
  inner join
  (
    select 
      business_key, 
      max(id) as max_id
    from mytable
    group by
      business_key
  ) as drv on
    mytable.id = drv.max_id
于 2009-01-13T13:36:47.160 回答
3

试试这个

select  business_key, 
        result
from    myTable
where   id in 
        (select max(id)
        from    myTable
        group by business_key)

编辑：我创建了表来测试我的代码。我把它包括在下面，以防其他人想要测试它。

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[myTable](
    [id] [int] NOT NULL,
    [business_key] [int] NOT NULL,
    [result] [int] NOT NULL
) ON [PRIMARY]
go

insert into myTable values(1,1,0);
insert into myTable values(2,1,1);
insert into myTable values(3,2,1);
insert into myTable values(4,3,1);
insert into myTable values(5,4,1);
insert into myTable values(6,4,0);

select  * from mytable
于 2009-01-13T13:42:03.157 回答
2 
select business_key, 
       result
    from 
    (select id, 
        business_key, 
        result, 
        max(id) over (partition by business_key) as max_id
    from mytable) x
where id = max_id
于 2009-01-15T00:49:36.897 回答
2

这是一篇较旧的帖子，但与我目前正在做的事情有关（2013 年）。如果您获得更大的数据集（在大多数数据库中很典型），则各种查询的性能（查看执行计划）说明了很多。首先我们创建一个“TALLY 表”来随机生成数字，然后使用任意公式为“MyTable”创建数据： 

CREATE TABLE #myTable(
    [id] [int] NOT NULL,
    [business_key] [int] NOT NULL,
    [result] [int] NOT NULL,
    PRIMARY KEY (Id)
) ON [PRIMARY];

; WITH
    -- Tally table Gen            Tally Rows:     X2                X3
t1 AS (SELECT 1 N UNION ALL SELECT 1 N),    -- 4            ,    8
t2 AS (SELECT 1 N FROM t1 x, t1 y),            -- 16            ,    64
t3 AS (SELECT 1 N FROM t2 x, t2 y),            -- 256            ,    4096
t4 AS (SELECT 1 N FROM t3 x, t3 y),            -- 65536        ,    16,777,216
t5 AS (SELECT 1 N FROM t4 x, t4 y),            -- 4,294,967,296,    A lot
Tally AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) N
          FROM t5 x, t5 y)

INSERT INTO #MyTable 
SELECT N, CAST(N/RAND(N/8) AS bigINT)/5 , N%2
FROM Tally
WHERE N < 500000

接下来我们运行三种不同类型的查询来检查性能（如果您使用的是 SQL Server Management Studio，请打开“实际执行计划”）：

SET STATISTICS IO ON
SET STATISTICS TIME ON
----- Try #1 
select  'T1' AS Qry, id, business_key, 
        result
from    #myTable
where   id in 
        (select max(id)
        from    #myTable
        group by business_key)

---- Try #2 
select 'T2' AS Qry, id, business_key, 
       result
    from 
    (select id, 
        business_key, 
        result, 
        max(id) over (partition by business_key) as max_id
    from #mytable) x
where id = max_id

---- Try #3 
;with cteRowNumber as (
    select id, 
        business_key, 
        result,
           row_number() over(partition by business_key order by id desc) as RowNum
        from #mytable
)

SELECT 'T3' AS Qry, id, business_key, 
       result
FROM cteRowNumber
WHERE RowNum = 1

清理：

IF OBJECT_ID(N'TempDB..#myTable',N'U') IS NOT NULL 
    DROP TABLE #myTable;
    SET STATISTICS IO OFF
SET STATISTICS TIME OFF

你会发现，查看执行计划，“Try 1”具有最好的“查询成本”和最低的 CPU 时间，但“Try 3”的读取次数最少，CPU 时间也不算太差。我建议使用 CTE 方法来减少读取次数

于 2013-09-27T14:41:35.433 回答