我不认为我的标题可以解释这个问题，所以这里是问题：
详细信息 build.sbt：
name := "Hello"
scalaVersion := "2.11.8"
version := "1.0"
libraryDependencies += "org.apache.spark" %% "spark-core" % "2.1.0"
libraryDependencies += "org.apache.spark" %% "spark-sql" % "2.1.0"
libraryDependencies += "org.apache.spark" % "spark-hive_2.11" % "2.1.0"
代码：
val sparkSession = SparkSession.builder().enableHiveSupport().appName("HiveOnSpark").master("local").getOrCreate()
val hiveql : HiveContext = new HiveContext(sparkSession.sparkContext);
hiveql.sql("drop table if exists test")
hiveql.sql("create table test (id int, name string) stored as orc tblproperties(\"transactional\"=\"true\")")
hiveql.sql("insert into test values(1,'Yash')")
hiveql.sql("insert into test values(2,'Yash')")
hiveql.sql("insert into test values(3,'Yash')")
hiveql.sql("select * from test").show()
hiveql.sql("delete from test where id= 1")
问题：
Exception in thread "main" org.apache.spark.sql.catalyst.parser.ParseException:
Operation not allowed: delete from(line 1, pos 0)
== SQL ==
delete from test where id= 1
^^^
at org.apache.spark.sql.catalyst.parser.ParserUtils$.operationNotAllowed(ParserUtils.scala:39)
at org.apache.spark.sql.execution.SparkSqlAstBuilder$$anonfun$visitFailNativeCommand$1.apply(SparkSqlParser.scala:925)
at org.apache.spark.sql.execution.SparkSqlAstBuilder$$anonfun$visitFailNativeCommand$1.apply(SparkSqlParser.scala:916)
at org.apache.spark.sql.catalyst.parser.ParserUtils$.withOrigin(ParserUtils.scala:93)
at org.apache.spark.sql.execution.SparkSqlAstBuilder.visitFailNativeCommand(SparkSqlParser.scala:916)
at org.apache.spark.sql.execution.SparkSqlAstBuilder.visitFailNativeCommand(SparkSqlParser.scala:52)
at org.apache.spark.sql.catalyst.parser.SqlBaseParser$FailNativeCommandContext.accept(SqlBaseParser.java:952)
at org.antlr.v4.runtime.tree.AbstractParseTreeVisitor.visit(AbstractParseTreeVisitor.java:42)
at org.apache.spark.sql.catalyst.parser.AstBuilder$$anonfun$visitSingleStatement$1.apply(AstBuilder.scala:66)
at org.apache.spark.sql.catalyst.parser.AstBuilder$$anonfun$visitSingleStatement$1.apply(AstBuilder.scala:66)
at org.apache.spark.sql.catalyst.parser.ParserUtils$.withOrigin(ParserUtils.scala:93)
at org.apache.spark.sql.catalyst.parser.AstBuilder.visitSingleStatement(AstBuilder.scala:65)
at org.apache.spark.sql.catalyst.parser.AbstractSqlParser$$anonfun$parsePlan$1.apply(ParseDriver.scala:54)
at org.apache.spark.sql.catalyst.parser.AbstractSqlParser$$anonfun$parsePlan$1.apply(ParseDriver.scala:53)
at org.apache.spark.sql.catalyst.parser.AbstractSqlParser.parse(ParseDriver.scala:82)
at org.apache.spark.sql.execution.SparkSqlParser.parse(SparkSqlParser.scala:45)
at org.apache.spark.sql.catalyst.parser.AbstractSqlParser.parsePlan(ParseDriver.scala:53)
at org.apache.spark.sql.SparkSession.sql(SparkSession.scala:592)
at org.apache.spark.sql.SQLContext.sql(SQLContext.scala:699)
at main.scala.InitMain$.delayedEndpoint$main$scala$InitMain$1(InitMain.scala:41)
at main.scala.InitMain$delayedInit$body.apply(InitMain.scala:9)
at scala.Function0$class.apply$mcV$sp(Function0.scala:34)
at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
at scala.App$$anonfun$main$1.apply(App.scala:76)
at scala.App$$anonfun$main$1.apply(App.scala:76)
at scala.collection.immutable.List.foreach(List.scala:381)
at scala.collection.generic.TraversableForwarder$class.foreach(TraversableForwarder.scala:35)
at scala.App$class.main(App.scala:76)
at main.scala.InitMain$.main(InitMain.scala:9)
at main.scala.InitMain.main(InitMain.scala)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:147)
更新查询同样的问题。
所以现在我已经完成了这个、这个、更新 Spark SQL 中的查询、这个、这个和许多其他的查询。
我知道 Spark 不支持更新/删除，但我处于需要同时使用这两种操作的情况。任何人都可以以某种方式建议/帮助。