9

我覆盖默认模型 AbstractUse 以通过电子邮件进行授权。

应用程序.account.models.py

# -*- coding: utf-8 -*-
import datetime

from django.db import models
from django.contrib.auth.models import AbstractUser

class User(AbstractUser):

class Meta(AbstractUser.Meta):
    swappable = 'AUTH_USER_MODEL'

USERNAME_FIELD = 'email'

applications.account.admin.py 并在 admin.py 文件中使用我的自定义用户。我试图取消注册默认用户模型并注册自定义。

# -*- coding: utf-8 -*-
from django.contrib import admin
from django.http import HttpResponseRedirect
from django.contrib.auth.models import User

from modeltranslation.admin import TabbedTranslationAdmin
from applications.account.models import Profile, Phone, ShippingAddress, PartnerGC, Referral, Operation
from applications.account.models import User as MyUser


class UserInline(admin.StackedInline):
    model = Profile
    max_num = 1
    can_delete = False


class OperationInline(admin.StackedInline):
    model = Operation
    can_delete = True


class PhoneInline(admin.StackedInline):
    model = Phone
    can_delete = True


class PartnerGCInline(admin.StackedInline):
    model = PartnerGC
    max_num = 1
    can_delete = True


class ReferralInline(admin.StackedInline):
    model = Referral
    max_num = 1
    can_delete = True


class ShippingAddressInline(admin.StackedInline):
    model = ShippingAddress
    can_delete = True


class ProfileAdmin(admin.ModelAdmin):
    list_filter = ["date_joined"]
    search_fields = ["=id", "first_name", 'last_name', "email"]
    list_display = ('id', "email", 'first_name', 'last_name', 'date_joined',
                    'last_login')
    actions = ['mark_active', 'mark_inactive']
    inlines = [UserInline, PhoneInline, ShippingAddressInline, PartnerGCInline, ReferralInline, OperationInline]

    def user_email(self, instance):
        return instance.user.email
    user_email.short_description = u"E-mail"

    def user_active(self, instance):
        return instance.user.is_active
    user_active.short_description = u"Активен"
    user_active.boolean = True

    def user_staff(self, instance):
        return instance.user.is_staff
    user_staff.short_description = u"Персонал"
    user_staff.boolean = True

    def user_superuser(self, instance):
        return instance.user.is_superuser
    user_superuser.short_description = u"Администратор"
    user_superuser.boolean = True

    def user_date_joined(self, instance):
        return instance.user.date_joined
    user_date_joined.short_description = u"Дата регистрации"

    def user_last_login(self, instance):
        return instance.user.last_login
    user_last_login.short_description = u"Последняя активность"

    def mark_active(self, request, queryset):
        queryset.update(user__is_active=True)
        return HttpResponseRedirect('')
    mark_active.short_description = u"Активировать выбранные профили"

    def mark_inactive(self, request, queryset):
        queryset.update(user__is_active=False)
        return HttpResponseRedirect('')

admin.site.unregister(User)
admin.site.register(MyUser, ProfileAdmin)
4

2 回答 2

9

如果您已将设置AUTH_USER_MODEL设置为自定义模式，则User不应注册默认应用程序。因此，您应该删除试图取消注册默认用户模型的行：

admin.site.unregister(User)
于 2017-04-24T09:31:56.380 回答
2

在django-hijack-admin 文档中，有一个自定义管理员部分：

你需要HIJACK_REGISTER_ADMIN = False在settings.py中设置

对于自定义用户管理员，管理员类可以修改如下：

# admin.py
from hijack_admin.admin import HijackUserAdminMixin

class MyUserAdmin(UserAdmin, HijackUserAdminMixin):
    list_display = (
        ...
        'hijack_field',  # Hijack button
    )

对于具有 User 外键的模型，可以使用 mixin，如下所示：

#admin.py
from django.contrib import Admin
from hijack_admin.admin import HijackRelatedAdminMixin

class MyCustomerAdmin(HijackRelatedAdminMixin, admin.ModelAdmin)
    list_display = ('user', 'hijack_field')
于 2019-08-15T20:49:35.143 回答