(已编辑)我正在研究 verilog 算术项目,但我被卡在了符号扩展部分(假设这是问题所在)。我有 4 位输入 A、B,应该有 8 位输出。对于某些过程(总和,子...),我需要使用符号扩展来制作 8 位输出。所以对于算术的主体,我有这个代码。这是代码的一半。我没有包括一半因为它只是长..
module arithmetic(A, B, AN0, DP, sum, sub, mult, div, comp, shiftLeft,
shiftRight, signExtend);
input signed [3:0] A, B;
output [7:0] sum, sub, mult, div, comp, shiftLeft, shiftRight,
signExtend;
output AN0, DP;
//sum
reg [4:0] qsum;
always@ (A, B)
qsum = A+B;
assign sum = {{3{qsum[4]}},qsum};
//sub
reg [4:0] qsub;
always@ (A, B)
qsub = A-B;
assign sub = {{3{qsub[4]}},qsub};
//mult
reg [7:0] qmult;
always@ (A, B)
qmult = A * B;
assign mult = qmult;
当我检查我的模拟时,它除了 Z 和 Xs 之外没有任何值。它甚至不显示任何输入值。为什么会这样??谢谢你
(已编辑)这是我的测试台代码。有 8 种操作(求和、减法、乘法、除法、比较器、左移、右移、符号扩展)
module lap3_top_tb();
reg signed [3:0] A, B;
reg [2:0] Operation;
wire [7:0] Result;
wire DP, AN0;
lab3_top ulap3_top(
.A(A),
.B(B),
.Operation(Operation),
.Result(Result),
.DP(DP),
.AN0(AN0)
);
initial begin
A = 6; B = 7; Operation = 0;
#20;
A = -6; B = -7; Operation = 0;
#20;
A = 6; B = 7; Operation = 1;
#20;
A = -6; B = -7; Operation = 1;
#20;
A = 6; B = 7; Operation = 2;
#20;
A = -6; B = 7; Operation = 2;
#20;
A = 7; B = 4; Operation = 3;
#20;
A = 7; B = 0; Operation = 3;
#20;
A = 6; B = 7; Operation = 4;
#20;
A = -6; B = -7; Operation = 4;
#20;
A = 1; B = 6; Operation = 5;
#20;
A = 1; B = -6; Operation = 5;
#20;
A = 1; B = 6; Operation = 6;
#20;
A = 1; B = -6; Operation = 6;
#20;
A = 6; B = 0; Operation = 7;
#20;
A = -5; B = 0; Operation = 7;
#20;
end
endmodule
lap3_top 文件在这里。(mux_8_1 将选择输出并通过结果输出。如果您需要代码,请告诉我!但我认为 mux 工作正常)
module lap3_top(A, B, Operation, Result, AN0, DP);
input signed [3:0] A, B;
input [2:0] Operation;
output AN0, DP;
output [7:0] Result;
wire a, b, c, d, e, f, g, h;
arithmetic uarithmetic(
.A(A),
.B(B),
.AN0(AN0),
.DP(DP),
.sum(a),
.sub(b),
.mult(c),
.div(d),
.comp(e),
.shiftLeft(f),
.shiftRight(g),
.signExtend(h)
);
mux_8_1 umux8_1(
.A(a),
.B(b),
.C(c),
.D(d),
.E(e),
.F(f),
.G(g),
.H(h),
.Operation(Operation),
.Result(Result)
);
endmodule
十分感谢大家!