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最近我又给了 Dashcode 一个机会;)

这很棒。只是我认为没有很好的记录。我有一个 stackLayout 对象,其中只有两个视图,还有几个按钮可以将视图与转换交换。(视图显示大数组的数据,list)动画和转换工作完美。问题是,当我在制作动画时按下一个按钮,动画又开始了,它看起来很难看(如果我有 n 个长度为 n 的数据源数组的视图,这应该不是问题,但这不是我的情况)。

我想在动画发生时禁用按钮。

动画完成后,是否有任何回调、委托或任何方式可以获得通知?

这就是我所做的:

function _changeView(transitionDirection, newIndex){

    //Create transition
    var newTransition = new Transition(Transition.SWAP_TYPE, 0.9, Transition.EASE_TIMING);
    newTransition.direction = transitionDirection;

    //I only have two views. I use currentView's id to calculate not current view id and change text inside of it. 
    var stackLayout = document.getElementById('stackLayout').object;//stackLayout object
    var nextViewId = (stackLayout.getCurrentView().id == 'view1')? '2':'1'; //

    //change the text in the view that is going to appear   
    document.getElementById('text'+nextViewId).innerHTML = list[curIndex];

    stackLayout.setCurrentViewWithTransition('view'+ nextViewId, newTransition, false);
}

function goPrevious(event)
{
    curIndex--;
    if(curIndex < 0){ 
        curIndex = list.length-1;
    }
    _changeView(Transition.LEFT_TO_RIGHT_DIRECTION, curIndex);
}

function goNext(event)
{
    curIndex++;
    if(curIndex >list.length - 1){ 
        curIndex = 0;
    }
    _changeView(Transition.RIGHT_TO_LEFT_DIRECTION, curIndex);
}
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1 回答 1

2

终于找到了这个问题的答案。我是这样做的:

document.getElementById('stackLayout').object.endTransitionCallback=function(stackLayout, oldView, newView) {
    //PUT CODE HERE USING stackLayout, oldView, newView to show params
}

事实上你可以在你的项目的 StackLayout.js 文件中找到所有的 stackLayout 方法和属性!!

希望这可以帮助

于 2011-02-02T19:21:25.743 回答