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基本上我想要的是用实际实体替换文本中的所有代词。

        // Path to the folder with models extracted from `stanford-corenlp-3.7.0-models.jar`
        var jarRoot = ...

        // Text for processing
        var text = "Kosgi Santosh sent an email to Stanford University. He didn't get a reply.";

        // Annotation pipeline configuration
        var props = new Properties();
        props.setProperty("annotators", "tokenize, ssplit, pos, lemma, ner, parse, dcoref");
        props.setProperty("ner.useSUTime", "0");

        // We should change current directory, so StanfordCoreNLP could find all the model files automatically
        var curDir = Environment.CurrentDirectory;
        Directory.SetCurrentDirectory(jarRoot);
        var pipeline = new StanfordCoreNLP(props);
        Directory.SetCurrentDirectory(curDir);

        // Annotation
        var annotation = new Annotation(text);
        pipeline.annotate(annotation);

        var graph = annotation.get(new CorefChainAnnotation().getClass());
        Console.WriteLine(graph);

到目前为止，我只能找到如何“漂亮地打印”它，但我想进一步处理来自“graph”的结果，但我不知道如何实际解析来自“annotation.get(new CorefChainAnnotation().获取类（））”。在 Java 中，据说它会返回一个 Map < Integer, CorefChain >，但我不知道它应该如何在 C# 中工作。

你有什么想法？

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1 回答 1

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一旦你有了注释，你就可以通过投射它来获得图形。

Map graph = (Map)document.get(new CorefCoreAnnotations.CorefChainAnnotation().getClass());
var entrySetValues = graph.entrySet();
Iterator it = entrySetValues.iterator();
while (it.hasNext())
{
     Map.Entry kvpair = (Map.Entry)it.next();
     CorefChain corefChain = (CorefChain)kvpair.getValue();
     var mentionsList = corefChain.getMentionsInTextualOrder() as ArrayList;
     foreach (CorefMention mention in mentionsList)
     {
          string noun = mention.mentionSpan;
          // do other stuff
     } 

     it.remove();
}

对于C#，想法是首先正确地转换对象，从转换对象中获取列表作为ArrayList，在arraylist上循环并再次正确地转换对象。

于 2017-08-28T04:59:09.290 回答