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我有颜色 UIColor(displayP3Red: 1, green: 0, blue: 0.8, alpha: 1)。我想创建一个去饱和的版本——具有相同的色调和亮度，但饱和度较低，就像原始饱和度的一半。我该怎么做呢？

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2 回答 2

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它应该很简单，因为您可以计算 DCI-P3 的归一化主矩阵 (NPM)：NPM 的中间行代表亮度因子。我将使用Color来说明这一点，它假设您使用的是线性值：

import numpy as np
import colour

# Computing the sRGB Luminance Equation, you should be familiar with the 
# resulting Luminance factors.
print(colour.RGB_luminance_equation(
    colour.sRGB_COLOURSPACE.primaries, 
    colour.sRGB_COLOURSPACE.whitepoint))
# Y = 0.212639005872(R) + 0.715168678768(G) + 0.0721923153607(B)

# Computing the DCI-P3 Luminance Equation.
print(colour.RGB_luminance_equation(
    colour.DCI_P3_COLOURSPACE.primaries, 
    colour.DCI_P3_COLOURSPACE.whitepoint))
# Y = 0.209491677913(R) + 0.721595254161(G) + 0.0689130679262(B)

# Computing Luminance of given RGB colour, this is assuming it is representing linear values.
DCI_P3_LUMINANCE_FACTORS = np.array([0.209491677913, 0.721595254161, 0.0689130679262])
RGB = np.array([1.0, 0.0, 0.8])
Y = np.dot(RGB, DCI_P3_LUMINANCE_FACTORS)
print(Y)
# 0.264622132254

Y代表给定颜色的亮度，如果你想在 50% 处去饱和，你可以这样做：

lerp(RGB, [Y, Y, Y], 0.5)

于 2017-03-31T20:54:50.980 回答
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extension UIColor {    
  // Calling this with 0.5 as argument returns a color whose saturation is 50% of that of the receiver.
  func desaturatedBy(fraction: CGFloat) -> UIColor {
    var hue: CGFloat = 0
    var saturation: CGFloat = 0
    var brightness: CGFloat = 0
    var alpha: CGFloat = 0
    let success = getHue(&hue, saturation: &saturation, brightness: &brightness, alpha: &alpha)
    assert(success)

    saturation *= fraction

    return UIColor(hue: hue, saturation: saturation, brightness: brightness, alpha: alpha)
  }
}

这是因为 getter 在扩展的 sRGB 颜色空间中返回 HSB，而 UIColor 的初始化程序也采用扩展的 sRGB 颜色空间中的 HSB。所以我们不需要做任何色彩空间转换。

于 2017-04-15T04:15:39.473 回答