python - 如何测试 Connexion/Flask 应用程序？

Question

我正在使用Flask的Connexion框架来构建微服务。我想为我的应用程序使用.py.test

在pytest-flask文档中，它说要创建一个固定装置conftest.py来创建应用程序，如下所示：

conftest.py

import pytest

from api.main import create_app


@pytest.fixture
def app():
    app = create_app()
    return app

在我的测试中，我使用这样的client夹具：

test_api.py

def test_api_ping(client):
    res = client.get('/status')
    assert res.status == 200

但是，当我运行时，py.test我收到以下错误消息：

==================================== ERRORS ====================================
_______________________ ERROR at setup of test_api_ping ________________________

request = <SubRequest '_monkeypatch_response_class' for <Function 'test_api_ping'>>
monkeypatch = <_pytest.monkeypatch.MonkeyPatch instance at 0x7f9f76b76518>

    @pytest.fixture(autouse=True)
    def _monkeypatch_response_class(request, monkeypatch):
        """Set custom response class before test suite and restore the original
        after. Custom response has `json` property to easily test JSON responses::
    
            @app.route('/ping')
            def ping():
                return jsonify(ping='pong')
    
            def test_json(client):
                res = client.get(url_for('ping'))
                assert res.json == {'ping': 'pong'}
    
        """
        if 'app' not in request.fixturenames:
            return
    
        app = request.getfuncargvalue('app')
        monkeypatch.setattr(app, 'response_class',
>                           _make_test_response_class(app.response_class))
E       AttributeError: 'App' object has no attribute 'response_class'

我怎样才能py.test工作？这是我的create_app功能：

main.py

import connexion


def create_app():
    app = connexion.App(__name__, port=8002,)
    app.add_api('swagger.yaml')
    return app


if __name__ == "__main__":
    create_app().run()

Answer 1

使用固定装置

test_api.py

import pytest
import connexion

flask_app = connexion.FlaskApp(__name__)
flask_app.add_api('swagger.yml')


@pytest.fixture(scope='module')
def client():
    with flask_app.app.test_client() as c:
        yield c


def test_health(client):
    response = client.get('/health')
    assert response.status_code == 200

招摇.yml

swagger: '2.0'
info:
  title: My API
  version: '1.0'
consumes:
  - application/json
produces:
  - application/json
schemes:
  - https
paths:
  /health:
    get:
      tags: [Health]
      operationId: api.health
      summary: Health Check
      responses:
        '200':
          description: Status message from server describing current health

api.py

def health():
    return {'msg': 'ok'}, 200

使用 Swagger 测试器

使用swagger-tester 的另一种解决方案：

test_api.py

from swagger_tester import swagger_test

authorize_error = {
    'get': {
        '/health': [200],
    }
}

def test_swagger():
    swagger_test('swagger.yml', authorize_error=authorize_error)

这个库很酷的一点是，您可以使用规范中提供的示例。但我认为它不能开箱即用connexion.RestyResolver：您必须在每个端点指定 OperationId。

Answer 2