我有一个托管在 GAE 上的简单应用程序(java servlet)。该应用程序返回 json 数据。我在 servlet 中将标头信息设置如下:
resp.setContentType("application/json");
resp.setHeader("Access-Control-Allow-Origin", "*");
resp.setHeader("Access-Control-Allow-Methods", "GET, POST, OPTIONS");
resp.setHeader("Access-Control-Allow-Credentials", "true");
这是我直接在应用引擎上访问 URL 时的标题信息:
Request Method:GET
Status Code:200 OK
Request Headersview source
Accept:text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Charset:ISO-8859-1,utf-8;q=0.7,*;q=0.3
Accept-Encoding:gzip,deflate,sdch
Accept-Language:en-US,en;q=0.8
Cache-Control:max-age=0
Connection:keep-alive
Host:---------.appspot.com
User-Agent:Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.19 (KHTML, like Gecko) Chrome/18.0.1025.162 Safari/535.19
Response Headersview source
Access-Control-Allow-Credentials:true
Access-Control-Allow-Methods:GET, POST, OPTIONS
Access-Control-Allow-Origin:*
Cache-Control:private
Content-Encoding:gzip
Content-Length:340
Content-Type:application/json; charset=ISO-8859-1
Date:Sat, 28 Apr 2012 19:14:58 GMT
Server:Google Frontend
Vary:Accept-Encoding
但是当我尝试从不同的域访问 url 时,我得到以下响应:
Request Method:OPTIONS
Status Code:500 Internal Server Error
Request Headersview source
Accept:*/*
Accept-Charset:ISO-8859-1,utf-8;q=0.7,*;q=0.3
Accept-Encoding:gzip,deflate,sdch
Accept-Language:en-US,en;q=0.8
Access-Control-Request-Headers:origin, x-requested-with, accept
Access-Control-Request-Method:GET
Connection:keep-alive
Host:----------.appspot.com
Origin:http://--------------.com
Referer:http://-------------.com/map/
User-Agent:Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.19 (KHTML, like Gecko) Chrome/18.0.1025.162 Safari/535.19
Response Headersview source
Content-Length:466
Content-Type:text/html; charset=UTF-8
Date:Sat, 28 Apr 2012 19:15:14 GMT
Server:Google Frontend
这是确切的错误:
XMLHttpRequest cannot load http://----------.appspot.com/Locations. Origin http://-------------.com is not allowed by Access-Control-Allow-Origin.
尝试访问 GAE url 的代码如下所示:
$.getJSON("http://---------appspot.com/Locations",function(result){
for (i=0; i < result.length; i++)
任何帮助将不胜感激。