1

我正在使用 python 开发基于文本的冒险游戏。现在我有它，所以主游戏循环总是打印“你想做什么？” 并将输入拆分为单个单词。

我有一个名为检查（也检查、观察、查看等）的操作，如果输入中有该单词，它将检查我在字典中描述的所有项目，如果找到，则打印项目的描述。

我怎样才能做到这一点，如果用户输入的单词都不在字典中，它会打印特定的消息？

#The dictionary of objects
objects = { #BUNCH OF DICTIONARY ENTRIES }
#The dictionary of checkable things other than the object list
check_dic = [{ #DICTIONARY },
             { #ANOTHER DICTIONARY },
             { #AND SO ON },
             { #AND SO FORTH}]

direct_dic = [{ #ANTOTHER LIST OF DICTIONARIES}]

#The beginning of the game.
print("Awaken adventurer, your journey begins here. What is your name?")
name = input('Enter your name:') #Sets the player's name.
print("Greetings, ", name, ". \nYou awaken in an unknown location equipped with only your trusty dagger, a strange vial, and a small pouch of gold coins.", sep= '')

player = "alive"
playerlocation = "room_1"
door1_state = "locked"
drawer_state = "locked"
trunk_state = "locked"
doorway_state = "locked"
plaque_state = "concealed"
bottle = "empty"
void_puzzle = 0
actions = ["check", "get", "drop", "use", "open", "orient", "go", "record", "read", "debugwarp"]
synonyms = ["look", "take", "examine", "observe", "pickup", "discard", "move"]

#The stone pile
s = 0

while player == "alive" and void_puzzle != "solved":
    #print(playerlocation) #this is for checking what room the player is in at any time
    if playerlocation == "room_1": #starting room
        dictionary = check_dic[0]
        items = items_in_room[0]
        hidden = hidden_items[0]
        directs = direct_dic[0]
        orientation = orientations[0]
    elif playerlocation == "room_2": #the rift room
        dictionary = check_dic[1]
        items = items_in_room[1]
        hidden = hidden_items[1]
        directs = direct_dic[1]
        orientation = orientations[1]
    #THERE'S A BUNCH OF LINES OMITTED THAT DO THE SAME THING FOR ALL OF THE OTHER ROOMS.
    print("What do you want to do?")
    userinput = input()
    userinput = userinput.lower()
    words = userinput.split()
    if actions[0] in words or synonyms[0] in words or synonyms[2] in words or synonyms[3] in words:
        for a in dictionary:
            if a in words:
                if a in dictionary:
                    if a == "drawer":
                        #A BUNCH OF STUFF RELATED SPECIFICALLY TO THE DRAWER
                    elif a == "desk":
                        #LIKEWISE
                    elif a == "trunk":
                        #ETC ETC THERE'S A BUNCH OF SPECIAL CASES HERE
                    else:
                        print(dictionary[a])
        for b in objects:
            if b in words:
                if b in inventory:
                    print(objects[b])
                else:
                    print("You can't check something you don't have.")

简而言之：我想要它，以便如果检查了单词并且输入不包含字典或对象中的任何内容，它会打印出像“你到底想检查什么？”这样的行。

有没有办法做到这一点？

4

0 回答 0