81

我在 Linux 上使用 Python 2.6。最快的方法是什么:

  • 确定哪个分区包含给定的目录或文件?

    例如,假设/dev/sda2安装在 上/home,并且/dev/mapper/foo安装在 上/home/foo"/home/foo/bar/baz"我想从字符串中恢复对("/dev/mapper/foo", "home/foo")

  • 然后,获取给定分区的使用统计信息?例如,假设/dev/mapper/foo我想获得分区的大小和可用空间(以字节为单位或大约以兆字节为单位)。

4

12 回答 12

130

这不会给出分区的名称,但您可以使用statvfsUnix 系统调用直接获取文件系统统计信息。要从 Python 调用它,请使用os.statvfs('/home/foo/bar/baz').

根据 POSIX,结果中的相关字段:

unsigned long f_frsize   Fundamental file system block size. 
fsblkcnt_t    f_blocks   Total number of blocks on file system in units of f_frsize. 
fsblkcnt_t    f_bfree    Total number of free blocks. 
fsblkcnt_t    f_bavail   Number of free blocks available to 
                         non-privileged process.

因此,要理解这些值,请乘以f_frsize

import os
statvfs = os.statvfs('/home/foo/bar/baz')

statvfs.f_frsize * statvfs.f_blocks     # Size of filesystem in bytes
statvfs.f_frsize * statvfs.f_bfree      # Actual number of free bytes
statvfs.f_frsize * statvfs.f_bavail     # Number of free bytes that ordinary users
                                        # are allowed to use (excl. reserved space)
于 2012-09-08T03:56:26.463 回答
50

如果您只需要设备上的可用空间,请参阅os.statvfs()下面的答案。

如果您还需要与文件关联的设备名称和挂载点,则应调用外部程序来获取此信息。df将提供您需要的所有信息——当它被调用时,df filename它会打印一行关于包含该文件的分区的信息。

举个例子:

import subprocess
df = subprocess.Popen(["df", "filename"], stdout=subprocess.PIPE)
output = df.communicate()[0]
device, size, used, available, percent, mountpoint = \
    output.split("\n")[1].split()

请注意,这相当脆弱,因为它取决于df输出的确切格式,但我不知道有更强大的解决方案。(有一些依赖于/proc下面文件系统的解决方案比这个更不便携。)

于 2010-11-23T19:53:45.737 回答
38

从 Python 3.3 开始,使用标准库可以轻松直接地执行此操作:

$ cat free_space.py 
#!/usr/bin/env python3

import shutil

total, used, free = shutil.disk_usage(__file__)
print(total, used, free)

$ ./free_space.py 
1007870246912 460794834944 495854989312

这些数字以字节为单位。有关更多信息,请参阅文档

于 2016-09-30T20:39:44.277 回答
25
import os

def get_mount_point(pathname):
    "Get the mount point of the filesystem containing pathname"
    pathname= os.path.normcase(os.path.realpath(pathname))
    parent_device= path_device= os.stat(pathname).st_dev
    while parent_device == path_device:
        mount_point= pathname
        pathname= os.path.dirname(pathname)
        if pathname == mount_point: break
        parent_device= os.stat(pathname).st_dev
    return mount_point

def get_mounted_device(pathname):
    "Get the device mounted at pathname"
    # uses "/proc/mounts"
    pathname= os.path.normcase(pathname) # might be unnecessary here
    try:
        with open("/proc/mounts", "r") as ifp:
            for line in ifp:
                fields= line.rstrip('\n').split()
                # note that line above assumes that
                # no mount points contain whitespace
                if fields[1] == pathname:
                    return fields[0]
    except EnvironmentError:
        pass
    return None # explicit

def get_fs_freespace(pathname):
    "Get the free space of the filesystem containing pathname"
    stat= os.statvfs(pathname)
    # use f_bfree for superuser, or f_bavail if filesystem
    # has reserved space for superuser
    return stat.f_bfree*stat.f_bsize

我的计算机上的一些示例路径名:

path 'trash':
  mp /home /dev/sda4
  free 6413754368
path 'smov':
  mp /mnt/S /dev/sde
  free 86761562112
path '/usr/local/lib':
  mp / rootfs
  free 2184364032
path '/proc/self/cmdline':
  mp /proc proc
  free 0

附言

如果在 Python ≥3.3 上,则返回以字节表示shutil.disk_usage(path)的命名元组。(total, used, free)

于 2010-12-27T09:57:23.843 回答
16

这应该使您所要求的一切:

import os
from collections import namedtuple

disk_ntuple = namedtuple('partition',  'device mountpoint fstype')
usage_ntuple = namedtuple('usage',  'total used free percent')

def disk_partitions(all=False):
    """Return all mountd partitions as a nameduple.
    If all == False return phyisical partitions only.
    """
    phydevs = []
    f = open("/proc/filesystems", "r")
    for line in f:
        if not line.startswith("nodev"):
            phydevs.append(line.strip())

    retlist = []
    f = open('/etc/mtab', "r")
    for line in f:
        if not all and line.startswith('none'):
            continue
        fields = line.split()
        device = fields[0]
        mountpoint = fields[1]
        fstype = fields[2]
        if not all and fstype not in phydevs:
            continue
        if device == 'none':
            device = ''
        ntuple = disk_ntuple(device, mountpoint, fstype)
        retlist.append(ntuple)
    return retlist

def disk_usage(path):
    """Return disk usage associated with path."""
    st = os.statvfs(path)
    free = (st.f_bavail * st.f_frsize)
    total = (st.f_blocks * st.f_frsize)
    used = (st.f_blocks - st.f_bfree) * st.f_frsize
    try:
        percent = ret = (float(used) / total) * 100
    except ZeroDivisionError:
        percent = 0
    # NB: the percentage is -5% than what shown by df due to
    # reserved blocks that we are currently not considering:
    # http://goo.gl/sWGbH
    return usage_ntuple(total, used, free, round(percent, 1))


if __name__ == '__main__':
    for part in disk_partitions():
        print part
        print "    %s\n" % str(disk_usage(part.mountpoint))

在我的盒子上打印上面的代码:

giampaolo@ubuntu:~/dev$ python foo.py 
partition(device='/dev/sda3', mountpoint='/', fstype='ext4')
    usage(total=21378641920, used=4886749184, free=15405903872, percent=22.9)

partition(device='/dev/sda7', mountpoint='/home', fstype='ext4')
    usage(total=30227386368, used=12137168896, free=16554737664, percent=40.2)

partition(device='/dev/sdb1', mountpoint='/media/1CA0-065B', fstype='vfat')
    usage(total=7952400384, used=32768, free=7952367616, percent=0.0)

partition(device='/dev/sr0', mountpoint='/media/WB2PFRE_IT', fstype='iso9660')
    usage(total=695730176, used=695730176, free=0, percent=100.0)

partition(device='/dev/sda6', mountpoint='/media/Dati', fstype='fuseblk')
    usage(total=914217758720, used=614345637888, free=299872120832, percent=67.2)
于 2011-06-18T16:54:12.873 回答
10

找出它的最简单方法。

import os
from collections import namedtuple

DiskUsage = namedtuple('DiskUsage', 'total used free')

def disk_usage(path):
    """Return disk usage statistics about the given path.

    Will return the namedtuple with attributes: 'total', 'used' and 'free',
    which are the amount of total, used and free space, in bytes.
    """
    st = os.statvfs(path)
    free = st.f_bavail * st.f_frsize
    total = st.f_blocks * st.f_frsize
    used = (st.f_blocks - st.f_bfree) * st.f_frsize
    return DiskUsage(total, used, free)
于 2015-08-06T13:11:45.853 回答
7

对于您问题的第二部分“获取给定分区的使用情况统计信息”,psutil使用disk_usage(path)函数使这变得容易。给定一个路径,disk_usage()返回一个命名元组,包括以字节表示的总空间、已用空间和可用空间,以及使用百分比。

文档中的简单示例:

>>> import psutil
>>> psutil.disk_usage('/')
sdiskusage(total=21378641920, used=4809781248, free=15482871808, percent=22.5)

Psutil 适用于从 2.6 到 3.6 的 Python 版本以及 Linux、Windows 和 OSX 以及其他平台。

于 2017-12-15T00:55:26.833 回答
6

对于第一点,您可以尝试使用os.path.realpath获取规范路径,检查它/etc/mtab(我实际上建议调用getmntent,但我找不到访问它的正常方式)以找到最长的匹配。(可以肯定的是,您可能应该stat同时使用文件和假定的挂载点来验证它们实际上是否在同一设备上)

对于第二点,用于os.statvfs获取块大小和使用信息。

(免责声明:我没有测试过这些,我所知道的大部分来自 coreutils 来源)

于 2010-11-23T20:36:49.207 回答
5
import os

def disk_stat(path):
    disk = os.statvfs(path)
    percent = (disk.f_blocks - disk.f_bfree) * 100 / (disk.f_blocks -disk.f_bfree + disk.f_bavail) + 1
    return percent


print disk_stat('/')
print disk_stat('/data')
于 2017-03-03T05:58:12.687 回答
1

通常/procLinux中的目录包含这样的信息,它是一个虚拟文件系统。例如,/proc/mounts提供有关当前已安装磁盘的信息;你可以直接解析它。实用程序之类的topdf都使用/proc

我没有使用它,但如果你想要一个包装器,这也可能有帮助:http: //bitbucket.org/chrismiles/psi/wiki/Home

于 2010-11-23T19:50:42.580 回答
1

检查 Windows PC 上的磁盘使用情况可以按如下方式完成:

import psutil

fan = psutil.disk_usage(path="C:/")
print("Available: ", fan.total/1000000000)
print("Used: ", fan.used/1000000000)
print("Free: ", fan.free/1000000000)
print("Percentage Used: ", fan.percent, "%")
于 2020-05-24T16:31:40.173 回答
0

11 年后,但扩展了其他答案。

import psutil

#File systems
value=psutil.disk_partitions()

for i in value:
    va=i[1]
    value2=psutil.disk_usage(va).percent
    print(value2)
    fs_space[va]=value2

这是将其添加到字典中,仅获取我需要的百分比,但您可以获取所有值或从总数、已使用、免费或百分比中选择您想要的值。

官方文档帮助很大

于 2021-12-30T22:15:04.917 回答