假设固定利率债券的时间表如下面的示例代码所示。
我可以通过使用该businessDaysBetween
功能获得男高音之间的天数。
现在我想要“时间价值”。有没有办法在不创建新功能的情况下做到这一点?
这是预期的结果:
May 14th, 2012 .5
November 14th, 2012 .5
May 14th, 2013 .5
November 14th, 2013 .5
May 14th, 2014 .5
November 14th, 2014 .5
May 14th, 2015 .5
November 16th, 2015 .505556
May 16th, 2016 .5
November 14th, 2016 .49444
这是代码:
from QuantLib import *
import pandas as pd
effective_date = Date(14, 11, 2011)
termination_date = Date(14, 11, 2016)
tenor = Period(Semiannual)
calendar = UnitedStates()
business_convention = ModifiedFollowing
termination_business_convention = Following
date_generation = DateGeneration.Forward
end_of_month = False
day_count = Thirty360()
schedule = Schedule(effective_date,
termination_date,
tenor,
calendar,
business_convention,
termination_business_convention,
date_generation,
end_of_month)
t = []
for i, d in enumerate(schedule):
tmp = i+1, d,
t.append(tmp)
df = pd.DataFrame(t,columns = ['tenorNo','tenorDate'])
nbDays = []
for x in df['tenorNo'] :
if x == 1:
tmp = 0
else:
tmp = calendar.businessDaysBetween(df['tenorDate'][x-2],df['tenorDate'][x-1])
nbDays.append(tmp)
df['nbDays'] = nbDays
print df
tenorNo tenorDate nbDays
0 1 November 14th, 2011 0
1 2 May 14th, 2012 125
2 3 November 14th, 2012 127
3 4 May 14th, 2013 124
4 5 November 14th, 2013 127
5 6 May 14th, 2014 124
6 7 November 14th, 2014 127
7 8 May 14th, 2015 124
8 9 November 16th, 2015 127
9 10 May 16th, 2016 125
10 11 November 14th, 2016 125