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我试图Map作为输入传递给我的orientdbgroovy 函数。但是 Groovy 函数将我的Map输入参数视为字符串。

请建议如何将 Map 类型的输入参数传递给 orientdb groovy 函数。

代码

public void MapInputTest() {
     Map < String, Object > inputMap = new HashMap < String, Object > ();
     inputMap.put("serviceId", "ETHA12721205");
     inputMap.put("serviceId1", "ETHA127212051");
     inputMap.put("serviceId2", "ETHA127212052");

     g.execute(Script.function("MapInputFunction", inputMap));
     System.out.println("returnedString is : ");
}

常规功能：

def MapInputFunction(Map mapInput) {
    println("class type of input parameter" + mapInput.getClass())
    println("class type " + mapInput)
    def tempMap = [: ]
    tempMap = mapInput
    return tempMap.get('serviceId')
}

错误

com.orientechnologies.orient.core.exception.OCommandExecutionException: Failed to execute command: function.MapInputFunction Cause:No signature of method: Script1.MapInputFunction() is applicable for argument types: (java.lang.String, java.lang.String, java.lang.String) values: [ETHA127212051, ETHA12721205, ETHA127212052]
    Possible solutions: MapInputFunction2(), MapInputFunction(java.lang.Object)
        at platform.orientdb.storage.DataGridStorage.executeCommand(DataGridStorage.java:631)
        at platform.orientdb.storage.DataGridStorage.command(DataGridStorage.java:601)
        at platform.orientdb.storage.message.CommandMessage.processMessage(CommandMessage.java:27)
        at platform.orientdb.storage.message.TxMessage.process(TxMessage.java:52)
        at platform.orientdb.storage.actor.TransactionActor.processMessage(TransactionActor.java:71)
        at platform.orientdb.storage.actor.ExternalStorageActor.onReceive(ExternalStorageActor.java:16)
        at akka.actor.UntypedActor$$anonfun$receive$1.applyOrElse(UntypedActor.scala:165)
        at akka.actor.Actor$class.aroundReceive(Actor.scala:484)
        at akka.actor.UntypedActor.aroundReceive(UntypedActor.scala:95)
        at akka.actor.ActorCell.receiveMessage(ActorCell.scala:526)
        at akka.actor.ActorCell.invoke(ActorCell.scala:495)
        at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:257)
        at akka.dispatch.Mailbox.run(Mailbox.scala:224)
        at akka.dispatch.Mailbox.exec(Mailbox.scala:234)
        at scala.concurrent.forkjoin.ForkJoinTask.doExec(ForkJoinTask.java:260)*emphasized text*
        at scala.concurrent.forkjoin.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:1339)
        at scala.concurrent.forkjoin.ForkJoinPool.runWorker(ForkJoinPool.java:1979)
        at scala.concurrent.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:107)
4

1 回答 1

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在脚本中，假设参数的名称是inputMap

然后发送以下

 Map < String, Object > parameters= new HashMap < String, Object > ();
     parameters.put("serviceId", "ETHA12721205");
     parameters.put("serviceId1", "ETHA127212051");

 Map < String, Object > inputMap = new HashMap < String, Object > ();
inputMap.put("inputMap",inputMap)

     g.execute(Script.function("MapInputFunction", inputMap));
     System.out.println("returnedString is : ");

该脚本将能够将 inputMap 读取为 Map 数据结构

于 2017-03-01T10:20:46.400 回答