我按照教程实现了谷歌的 Android 移动视觉。我正在尝试构建一个应用程序来扫描收据并查找数字总数。但是,当我扫描以不同格式打印的不同收据时,API 将以任意方式检测 TextBlocks。例如,在一张收据中,如果几个文本单词由单个空格分隔,那么它们将被分组到一个 TextBlock 中。但是,如果文本的两个单词被很多空格分隔,那么即使它们出现在同一“行”上,它们也会被分隔为独立的 TextBlock。我想要做的是强制 API 将收据的每一行识别为单个实体。这可能吗?
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public ArrayList<T> getAllGraphicsInRow(float rawY) {
synchronized (mLock) {
ArrayList<T> row = new ArrayList<>();
// Get the position of this View so the raw location can be offset relative to the view.
int[] location = new int[2];
this.getLocationOnScreen(location);
for (T graphic : mGraphics) {
float rawX = this.getWidth();
for (int i=0; i<rawX; i+=10){
if (graphic.contains(i - location[0], rawY - location[1])) {
if(!row.contains(graphic)) {
row.add(graphic);
}
}
}
}
return row;
}
}
这应该在 GraphicOverlay.java 文件中,并且基本上获取该行中的所有图形。
public static boolean almostEqual(double a, double b, double eps){
return Math.abs(a-b)<(eps);
}
public static boolean pointAlmostEqual(Point a, Point b){
return almostEqual(a.y,b.y,10);
}
public static boolean cornerPointAlmostEqual(Point[] rect1, Point[] rect2){
boolean almostEqual=true;
for (int i=0; i<rect1.length;i++){
if (!pointAlmostEqual(rect1[i],rect2[i])){
almostEqual=false;
}
}
return almostEqual;
}
private boolean onTap(float rawX, float rawY) {
String priceRegex = "(\\d+[,.]\\d\\d)";
ArrayList<OcrGraphic> graphics = mGraphicOverlay.getAllGraphicsInRow(rawY);
OcrGraphic currentGraphics = mGraphicOverlay.getGraphicAtLocation(rawX,rawY);
if (graphics !=null && currentGraphics!=null) {
List<? extends Text> currentComponents = currentGraphics.getTextBlock().getComponents();
final Pattern pattern = Pattern.compile(priceRegex);
final Pattern pattern1 = Pattern.compile(priceRegex);
TextBlock text = null;
Log.i("text results", "This many in the row: " + Integer.toString(graphics.size()));
ArrayList<Text> combinedComponents = new ArrayList<>();
for (OcrGraphic graphic : graphics) {
if (!graphic.equals(currentGraphics)) {
text = graphic.getTextBlock();
Log.i("text results", text.getValue());
combinedComponents.addAll(text.getComponents());
}
}
for (Text currentText : currentComponents) { // goes through components in the row
final Matcher matcher = pattern.matcher(currentText.getValue()); // looks for
Point[] currentPoint = currentText.getCornerPoints();
for (Text otherCurrentText : combinedComponents) {//Looks for other components that are in the same row
final Matcher otherMatcher = pattern1.matcher(otherCurrentText.getValue()); // looks for
Point[] innerCurrentPoint = otherCurrentText.getCornerPoints();
if (cornerPointAlmostEqual(currentPoint, innerCurrentPoint)) {
if (matcher.find()) { // if you click on the price
Log.i("oh yes", "Item: " + otherCurrentText.getValue());
Log.i("oh yes", "Value: " + matcher.group(1));
itemList.add(otherCurrentText.getValue());
priceList.add(Float.valueOf(matcher.group(1)));
}
if (otherMatcher.find()) { // if you click on the item
Log.i("oh yes", "Item: " + currentText.getValue());
Log.i("oh yes", "Value: " + otherMatcher.group(1));
itemList.add(currentText.getValue());
priceList.add(Float.valueOf(otherMatcher.group(1)));
}
Toast toast = Toast.makeText(this, " Text Captured!" , Toast.LENGTH_SHORT);
toast.show();
}
}
}
return true;
}
return false;
}
这应该在 OcrCaptureActivity.java 中,它将 TextBlock 分成几行,并在与该行相同的行中找到块,并检查组件是否都是价格,并相应地打印所有值。
mostEqual 中的 eps 值是它检查行中图形的高度的容差。
于 2017-12-08T20:02:53.373 回答