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我使用 3 个数组（用于 x、y 和半径大小）创建了 5 个具有随机 x 和 y 坐标和半径的圆。但是，我需要这些圆圈根据它们是否与另一个圆圈重叠来动态改变颜色。因此，如果 5 个圆圈中的一个完全不重叠，它应该是黑色的。重叠的圆圈应该是青色的。如果两个圆的中心点之间的距离小于它们的半径之和，则认为两个圆重叠。

这是我迄今为止为 circle 类所写的内容。下面的代码会成功在一个小程序窗口中绘制5个圆圈，并且距离计算成功，但问题在于着色。颜色填充似乎存在逻辑错误，我在这里看不到问题。有什么建议么？太感谢了。

public class Circles extends Applet {

public void paint(Graphics page)
{
    Random locator = new Random();
    int [] xpt = new int [5];
    int [] ypt = new int [5];
    int [] rad = new int [5];

    setPreferredSize (new Dimension(300, 300));
    for (int i = 0; i < xpt.length; i++){

        xpt[i] = locator.nextInt(100); //need to set a number or it goes into millions, cannot set it in Random()
        ypt[i] = locator.nextInt(100);
        rad[i] = locator.nextInt(100);
        System.out.println("The #" + i +  " x-point: " + xpt[i] + " y-point: " + ypt[i] + " radius: " + rad[i]);  //for debugging purposes

        for (int j = 0; j < xpt.length; j++){
            double xpoint1 = xpt[i]+rad[i];
            double ypoint1 = ypt[i]+rad[i];
            double xpoint2 = xpt[j]+rad[j];
            double ypoint2 = ypt[j]+rad[j];
            double radius1 = rad[i];
            double radius2 = rad[j];
            double theDistance = distance(xpoint1,ypoint1,xpoint2,ypoint2); 
            System.out.println("Comparing " + i + " to " + j); //for debugging and logic checking
            if (i==j)
                ;
            else if (theDistance <= (radius1+radius2))
            {
                page.setColor(Color.cyan);
                page.fillOval(xpt[i], ypt[i], rad[i], rad[i]);
                //page.fillOval(xpt[j], ypt[j], rad[j], rad[j]);
                System.out.println("Overlap occurred. Colored " + i + " and " + j + " cyan.");
                System.out.println("Center points: ("+ xpoint1 +", "+ ypoint1 +") and ("+ xpoint2 + ", "+ ypoint2 + ").");
            }
            else  
            {
                page.setColor(Color.black);
                page.fillOval(xpt[i], ypt[i], rad[i], rad[i]);
                //page.fillOval(xpt[j], ypt[j], rad[j], rad[j]);
                System.out.println("No overlap. Made " + i + " and " + j + " black.");
            }
        }
    }
}

public static double distance(
        double x1, double y1, double x2, double y2) {
    return Math.sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1));

}
}
4

2 回答 2

4

xpoint、ypoint 等线没有按照您的想法进行。

如果要查找两个圆是否重叠，则需要查找圆心之间的距离是大于还是小于它们的半径之和。

所以：

function circlesCollide(x1, y1, r1, x2, y2, r2){
    return (distance(x1, y1, x2, y2) <= (r1 + r2));
}
于 2010-11-13T04:16:23.270 回答
1

你为什么在+rad[]这里？您不必添加半径来比较距离。

        double xpoint1 = xpt[i]+rad[i];
        double ypoint1 = ypt[i]+rad[i];
        double xpoint2 = xpt[j]+rad[j];
        double ypoint2 = ypt[j]+rad[j];
 [...]
        double theDistance = distance(xpoint1,ypoint1,xpoint2,ypoint2); 
 [...]
        page.fillOval(xpt[i], ypt[i], rad[i], rad[i]);

您应该使用xpt/ypt表示距离。不是xpoint1，并使用-值和 2 * 半径的大小......即：

        double xpoint1 = xpt[i]-rad[i];
        double ypoint1 = ypt[i]-rad[i];
        double xpoint2 = xpt[j]-rad[j];
        double ypoint2 = ypt[j]-rad[j];
 [...]
        double theDistance = distance(xpt[i],ypt[i],xpt[j],ypt[j]); 
 [...]
        page.fillOval(xpoint1 , ypoint1, 2*rad[i], 2*rad[i]);
于 2010-11-13T04:12:00.630 回答