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Quanteda 包提供稀疏文档特征矩阵 DFM，其方法包含removeFeatures。我试图dfm(x, removeFeatures="\\b[a-z]{1-3}\\b")删除太短的单词以及dfm(x, keptFeatures="\\b[a-z]{4-99}\\b")保留足够长的单词但不起作用，基本上是在做同样的事情，即删除太短的单词。

如何从 Quanteda DFM 对象中删除正则表达式匹配？

例子。

myMatrix <-dfm(myData, ignoredFeatures = stopwords("english"), 
           stem = TRUE, toLower = TRUE, removeNumbers = TRUE, 
           removePunct = TRUE, removeSeparators = TRUE, language = "english")
#
#How to use keptFeatures/removeFeatures here?


#Instead of RemoveFeatures/keptFeatures methods, I tried it like this but not working
x<-unique(gsub("\\b[a-zA-Z0-9]{1,3}\\b", "", colnames(myMatrix))); 
x<-x[x!=""]; 
mmyMatrix<-myMatrix; 
colnames(mmyMatrix) <- x

示例 DFM

myData <- c("a aothu oat hoah huh huh huhhh h h h n", "hello h a b c d abc abcde", "hello hallo hei hej", "Hello my name is hhh.")
myMatrix <- dfm(myData)
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1 回答 1

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它dfm_select在 >= v0.9.9 中：

myMatrix
## Document-feature matrix of: 4 documents, 22 features (70.5% sparse).

dfm_select(myMatrix, "\\b[a-zA-Z0-9]{1,3}\\b", selection = "keep", valuetype = "regex")
## kept 14 features, from 1 supplied (regex) feature types
## Document-feature matrix of: 4 documents, 14 features (71.4% sparse).
## 4 x 14 sparse Matrix of class "dfmSparse"
##        features
## docs    a oat huh h n b c d abc hei hej my is hhh
##   text1 1   1   2 3 1 0 0 0   0   0   0  0  0   0
##   text2 1   0   0 1 0 1 1 1   1   0   0  0  0   0
##   text3 0   0   0 0 0 0 0 0   0   1   1  0  0   0
##   text4 0   0   0 0 0 0 0 0   0   0   0  1  1   1
于 2017-01-11T17:22:09.767 回答