python - Python/Tkinter：将 Tkinter 用于阿拉伯语/希伯来语等 RTL（从右到左）语言？

Question

是否可以使用 Tkinter 为 RTL 语言（如阿拉伯语或希伯来语）呈现用户界面？我尝试在“tkinter rtl”上搜索，搜索结果令人失望。Tk wiki表明目前不支持 bidi。

有人为阿拉伯语或希伯来语语言环境开发 Tkinter 应用程序吗？

Answer 1

我意识到这是一个老问题，但我昨天才开始使用 Tkinter 开发 Python 中的希伯来语应用程序。从右到左（bidi）作为框架的一部分不可用，但经过一些谷歌搜索和一些研究，我设法通过键绑定和强制重新定位光标令人信服地伪造它。我的 Entry 小部件保持左对齐，因此希伯来文文本与同一框中的某些英语的位置大致相同，但这种方法可以很容易地修改为右对齐框。（或者，右对齐可能会使这更简单）。尽管如此，这就是我所做的。

本质上，您在这里所做的是使用回调、字符代码和索引常量手动强制光标位置。此外，您必须考虑箭头键（我的行为就像在它们指向的方向上移动。我一直讨厌 RTL 通常如何反转箭头。不过，如果您愿意，这很容易改变。）退格键和德尔，此外，必须引起一些手动重新定位。当然，如果您手动跟踪光标，则必须更新跟踪变量，以防用户使用鼠标重新定位它。下面是我的代码，除了这里使用全局变量是为了消除解释中的一点复杂性。

             # Here, the necessary bindings.  We're going to 
             # have to make modifications on key press, release,
             # and on a completed mouse click.
             entryWidget.bind("<KeyPress>", rtlPress)
             entryWidget.bind("<KeyRelease>", rtlRelease)
             entryWidget.bind("<ButtonRelease>", rtlMouse)

接下来是三个回调函数，它们完成了我们所有的光标跟踪和重定位。

#With the following functions, keep in mind that we only want the cursor to move RIGHT
#(increase in index) in response to a right arrow press or a DEL.  Essentially, we are
#compensating for any movement but these explicit conditions.  Since the indexing of the 
#cursor position is LTR, holding it in its current position 
#while we append more text is 
#tantamount to moving it right.

#On key release, if an arrow key has been invoked, we update our tracking variable to 
#reflect the new cursor position.  If any other key was pressed, we snap the cursor back 
#to where it was prior to the keypress to prevent it from moving right and cause the
#next letter to be appended on the left side of the previous letter.

def rtlRelease(event):
        global hebCursorPos
        if event.keycode==114 or event.keycode==113:
               hebCursorPos=event.widget.index(INSERT)
        else:
               event.widget.icursor(hebCursorPos)
        print(str(event.keycode)+" "+str(hebCursorPos))

#On keypress, we must compensate for the natural LTR behavior of backspace(22) and
#del(119)

def rtlPress(event):
        global hebCursorPos
        #In LTR text entry, a backspace naturally removes the character to the left of
        #the cursor.
        if event.keycode==22:
               length =  len(event.widget.get())
               #In RTL, the right edge is the beginning of the string, so backspace
               #should do nothing.
               #If we're at the right edge of the string, we insert a meaningless
               #character to be deleted so that it appears to the user as if we have 
               #done nothing.
    if hebCursorPos==length:
                       event.widget.insert(hebCursorPos, " ")
               #In order to cause the backspace to delete the character to the right
               #rather than the left of the cursor from the user's perspective, we step 
               #the cursor forward one.  This will cause the backspace to delete the 
               #character to the left of the new cursor position, which will be the
               #character that was to the right of the cursor from the user's 
               #perspective.  If we were at the right end of the line, we insert a space 
               #and delete it milliseconds later.  We do not need to update the cursor's 
               #position, in the tracking variable, because after the character is 
               #deleted, it is back at the index from which it started, counting index
               #from an LTR perspective.
               event.widget.icursor(hebCursorPos+1)
        else:
               #Del is more of the same.  It deletes the character to the right of the
               #cursor, but we want it to delete the character to the right.
               if event.keycode==119:
               #If we're at the left edge of the string, insert a meaningless character
               #for the del to delete, so that from the user's perspective it does 
               #nothing.
                        if hebCursorPos==0:
                               event.widget.insert(hebCursorPos, " ")
                        #Otherwise, we will be stepping the cursor one to the left, so 
                        #that when it deletes the character to its new right, it will be 
                        #deleting the character from what the user thinks is its left.  
                        #Because we are deleting a character from the left of the cursor 
                        #from the user's perspective, there will be fewer characters to 
                        #the left of the cursor once the operation is complete.  As 
                        #cursor positioning is tracked as an LTR index, we must update
                        #our tracking variable.
                        else:
                                hebCursorPos-=1
                #Now, we snap our cursor to the position of our tracking variable.  
                #Either we are preventing it from drifting right due to overlapping 
                #keypresses, or we are repositioning it to maintain the correct index 
                #after a del.
                event.widget.icursor(hebCursorPos)

#Simply put, if the user repositions the cursor with the mouse, track it.
def rtlMouse(event):
         global hebCursorPos
         hebCursorPos=event.widget.index(INSERT)

希望这可以帮助！由于它是通过强制光标移动来完成的，因此在键入过程中会有轻微的视觉光标抖动，但文本排序似乎是正确的，并且当用户没有按中键时，光标似乎总是指示正确的位置。不过，我并没有声称代码完美！

Answer 2

这可能也不能解决整个问题，但它可以解决我认为主要问题的显示问题。

基本上你需要两件事来颠倒字符顺序并让它们连接在一起我使用了这个重塑器，它可以很好地处理没有变音符号的简单单词，الحركات但在某些情况下它仍然存在错误。

Answer 3

尝试将条目或其他元素设置为“jameel noori nastaleeq”或任何其他乌尔都语字体