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我正在升级我的代码以使用 Swift 3 和 CocoaLumberjack 3.0.0。当我为 iPhone 构建时,编译和链接成功。当我尝试为模拟器构建时,它会编译但不会链接。我收到了几条表单消息:

Undefined symbols for architecture x86_64: "CocoaLumberjack.DDLogDebug (@autoclosure () -> Swift.String, level : __C.DDLogLevel, context : Swift.Int, file : Swift.StaticString, function : Swift.StaticString, line : Swift.UInt, tag : Any?, asynchronous : Swift.Bool, ddlog : __ObjC.DDLog) -> ()", referenced from: ScanmonListener.SMLViewController.buttonTitle.didset : Swift.String in SMLViewController.o ScanmonListener.SMLViewController.viewDidLoad () -> () in SMLViewController.o ScanmonListener.SMLViewController.viewDidAppear (Swift.Bool) -> () in SMLViewController.o ScanmonListener.SMLViewController.viewDidDisappear (Swift.Bool) -> () in SMLViewController.o ScanmonListener.SMLViewController.viewWillAppear (Swift.Bool) -> () in SMLViewController.o ScanmonListener.SMLViewController.viewWillDisappear (Swift.Bool) -> () in SMLViewController.o ScanmonListener.SMLViewController.doPlay () -> Swift.Bool in SMLViewController.o ...

我已经运行pod deintegrate并再次安装,但没有任何效果。

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-->解决方案:在每个“Pod_”目标中,您必须添加x86_64(并且,也许,i386)到Valid Architectures构建设置。

于 2017-01-14T00:50:22.577 回答