0

我有以下课程：

public class Some implements Map<String, Object>{
    private Map<String, Object> innerMap;
    //implementation that can only set innerMap in constructor and cannot add or remove values
}

问题是我无法在杰克逊中正确反序列化它。如果我在没有默认类型的情况下进行序列化，那没关系，因为它被序列化为 {"one":"two"} 并正确反序列化（我必须使用

return new Some(jp.readValueAs(new TypeReference<HashMap<String,Object>>(){}));

当我使用打开的默认类型时，这被序列化为

["com.class.Some",{"one":"two"}]

但是反序列化正在抛出

com.fasterxml.jackson.databind.JsonMappingException: Unexpected token (START_OBJECT), expected START_ARRAY: need JSON Array to contain As.WRAPPER_ARRAY type information for class java.util.HashMap

有什么想法吗？

4

2 回答 2

0

这就是我需要的 - 自定义反序列化器：

public class SomeDeserializer extends JsonDeserializer<Some> {

    @Override
    public Object deserializeWithType(JsonParser jsonParser, DeserializationContext ctxt, TypeDeserializer typeDeserializer) throws IOException {
        return typeDeserializer.deserializeTypedFromObject(jsonParser, ctxt);
    }

    @SuppressWarnings("unchecked")
    @Override
    public Some deserialize(JsonParser jp, DeserializationContext ctxt)
            throws IOException {
        JsonDeserializer<Object> deserializer = ctxt.findRootValueDeserializer(
                ctxt.getTypeFactory().constructMapType(Map.class, String.class, Object.class));

        return new Some((Map) deserializer.deserialize(jp, ctxt, new HashMap<>()));
    }
}
于 2016-12-25T19:34:26.420 回答
0

使用以下命令注释您的构造函数@JsonCreator：

public static void main(String[] args) throws IOException {
    ObjectMapper mapper = new ObjectMapper();
    mapper.enableDefaultTyping(ObjectMapper.DefaultTyping.NON_FINAL);

    Some some = new Some(new HashMap<String, Object>() {{put("a", 1);}});

    String json = mapper.writeValueAsString(some);
    System.out.println("serialized  : " + json);

    some = mapper.readValue(json, Some.class);
    System.out.println("deserialized: " + some);
}

// Read only delegating Map
public static class Some extends AbstractMap<String, Object> {
    private Map<String, Object> delegate;

    @JsonCreator
    public Some(Map<String, Object> delegate) {
        this.delegate = Collections.unmodifiableMap(delegate);
    }

    @Override
    public Set<Entry<String, Object>> entrySet() {
        return delegate.entrySet();
    }
}
于 2016-12-24T21:33:17.347 回答