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我需要在我的应用程序中创建 firebase 深层链接，以便使用 UIActivityViewController 在不同平台上共享它们。为了创建这些链接，我使用以下代码和 URLQueryItem 来获取我将分享给其他应用程序的 url：

func createURLWithComponents(EventToUrl: Event) -> URL? {

    var urlComponents = URLComponents()
    urlComponents.scheme = "https"
    urlComponents.host = "www.example.com"
    urlComponents.path = "/"

    // add params
    let id = URLQueryItem(name: "id", value: EventToUrl.eventID)

    print(EventToUrl.name)
    let name = URLQueryItem(name: "name", value: EventToUrl.name)
    print(name.description)
    print(name.value)
    let photo = URLQueryItem(name: "photo", value:  EventToUrl.photoUrl)
    let created = URLQueryItem(name: "created", value: EventToUrl.creationDate )
    let participants = URLQueryItem(name: "participants", value: String(EventToUrl.Participants.count) )
    let place = URLQueryItem(name: "place", value: EventToUrl.Places[0].name)
    let time = URLQueryItem(name: "time", value: EventToUrl.time[0].TimestampString)
    urlComponents.queryItems = [id, name, photo, created, participants , place , time]

    let dynamicLinkDomain : String = "***.app.goo.gl"
    var deepLink = URLComponents()
    deepLink.scheme = "https"
    deepLink.host = dynamicLinkDomain
    deepLink.path = "/"

    let link = URLQueryItem(name: "link", value:  urlComponents.url?.absoluteString)
    let apn = URLQueryItem(name: "apn", value: "***" )
    let ibi = URLQueryItem(name: "ibi", value: "***" )
    let d = URLQueryItem(name: "d", value: "1")
    deepLink.queryItems = [link, apn, ibi, d]
    print(deepLink.url?.absoluteString)
    print(deepLink.url)

    return deepLink.url
}

这是我发送给他时的链接：

https://***.app.goo.gl/?link=https://www.example.com/?id%3D-KZYfNRCXdSqUG72FmEQ%26name%3Djeremie's%2520Event%26photo%3D%26created%3D%26participants%3D1%26place%3DLa%2520Piazza%26time%3D1482362284.50304&apn=***&ibi=***&d=1

https:// .app.goo.gl/?link= https://www.example.com/?id%3D-KZYfNRCXdSqUG72FmEQ%26name%3Djeremie的%2520Event%26photo%3D%26created%3D%26participants%3D1 %26place%3DLa%2520Piazza%26time%3D1482362284.50304&apn= &ibi=***&d=1

如您所见，如果事件名称由“'”字符（Jeremie 的事件）组成，则 URLQueryItem 未正确编码此字符（在我的 android 应用程序中，系统函数将其转换为“'”-> %27）我该如何编码？PS：我尝试addingPercentEncoding(withAllowedCharacters: .urlFragmentAllowed)没有成功...感谢您的帮助！

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1 回答 1

2

我找到了一个比其他解决方案更简单的解决方案。（至少对我来说）

我像往常一样构建了我的 URLComponents，但在从中获取 url 之前，我获取了 urlComponents.string 并用符号替换了特殊代码。我通过 addPercentEncoding 运行该字符串，然后从该字符串创建一个 url。

let stringWithoutBS = urlComponents.string!.replacingOccurrences(of: "%27", with: "'")
        //ignore the force unwrap

guard let encodedURL = stringWithoutBS.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed) else {
            print("unhelpful message")
            return nil
        }

var correctURL = URL(string: encodedURL)
于 2017-01-30T01:30:49.687 回答