javascript - 如何根据返回重复ajax请求

Question

我有这个代码：

.on('finish.countdown', function() {
                    var onEndAuction = function () {
                        $.ajax({
                            type: "POST",
                            url: "{{path('app_auction_end')}}",
                            data: {auctionId:{{ aReturn.oAuction.getId()}}},
                            success: function (data) {
                                console.log(data);
                                if (data == 0) {
                                    setTimeout(onEndAuction, i_timer);
                                } else {
                                    document.location.reload(true);
                                }
                            }
                        });
                    };
                });

我想如果 data == 0 需要app_auction_end在 10 秒后再次调用。你能帮我吗 ？提前谢谢，对不起我的英语

Answer 1

给操作一个命名函数：

var someFunction = function () {
    $.ajax({
        //...
    });
};

然后您将用于您的.on()通话：

.on('finish.countdown', someFunction)

在success处理程序中，为该函数设置超时：

if (data == 0) {
    setTimeout(someFunction, i_timer);
}

Answer 2

.on('finish.countdown', function() {
  var onEndAuction = function () {
    $.ajax({
      type: "POST",
      url: "{{path('app_auction_end')}}",
      data: {auctionId:{{ aReturn.oAuction.getId()}}},
      success: function (data) {
        console.log(data);
        if (data == 0) {
          setTimeout(onEndAuction, i_timer);
        } else {
          document.location.reload(true);
        }
      }
    });
  };
  //do our initial call otherwise it will never get called.
  onEndAuction();
});