3

我正在尝试在 Retrofit 中反序列化此类：

data class Measurement(val id: Long, val value: Float, val dateTime: LocalDateTime, val trashCanId: Long) : Parcelable {
    companion object {
        @JvmField val CREATOR: Parcelable.Creator<Measurement> = object : Parcelable.Creator<Measurement> {
            override fun createFromParcel(source: Parcel): Measurement = Measurement(source)
            override fun newArray(size: Int): Array<Measurement?> = arrayOfNulls(size)
        }
    }

    constructor(source: Parcel) : this(source.readLong(), source.readFloat(), source.readSerializable() as LocalDateTime, source.readLong())

    override fun describeContents() = 0

    override fun writeToParcel(dest: Parcel?, flags: Int) {
        dest?.writeLong(id)
        dest?.writeFloat(value)
        dest?.writeSerializable(dateTime)
        dest?.writeLong(trashCanId)
    }

}

如您所见，我使用的是 LocalDateTime，它来自 ThreeTen。好吧，我从我的服务器收到这个

    {
        "id": 1,
        "value": 50.6,
        "dateTime": {
          "hour": 2,
          "minute": 6,
          "second": 9,
          "nano": 0,
          "dayOfYear": 308,
          "dayOfWeek": "THURSDAY",
          "month": "NOVEMBER",
          "dayOfMonth": 3,
          "year": 2016,
          "monthValue": 11,
          "chronology": {
            "id": "ISO",
            "calendarType": "iso8601"
          }
        }
      }

好吧，但是我的 dateTime 始终为Null，所以我相信 Retrofit 不知道如何解析数据，或者我错过了什么？

有什么好的解决方法吗？

任何帮助表示赞赏！

4

2 回答 2

1

基于 Manoj Frekzz 的回答，我找到了我的解决方案......

首先我创建了一个 DateTimeDto。

data class DateTimeDto(val dayOfYear : Int, val dayOfWeek : String, val month : String, val dayOfMonth : Int,
                       val year : Int, val monthValue : Int, val hour : Int, val minute : Int, val second : Int,
                       val nano : Int, val chronology : Chronology)



fun toDateTime () : LocalDateTime{
     return LocalDateTime.of(year, monthValue, dayOfMonth, hour, minute)
}

我改变了接口的签名：

@GET("trashCan")

fun getLocalDateTime() : Observable<List<LocalDateTime>>

至：

@GET("trashCan")

fun getLocalDateTime() : Observable<List<DateTimeDto>>

然后，在我的观察者中，我这样做了：

ServiceGenerator.createService(ApiClient::class.java)
                .getLocalDateTime
                .map { it.map { it.toLocalDateTime() } }

它工作得很好......如果我改造可以自动反序列化它会更好，但这是一个很好的解决方法

于 2016-11-09T15:13:33.880 回答
1

首先添加这个gradle

 compile 'com.google.code.gson:gson:2.8.0'

然后添加这个类来保存json响应，

public class DemoResponse {
@com.google.gson.annotations.SerializedName("id")
public int id;
@com.google.gson.annotations.SerializedName("value")
public double value;

public int getId() {
    return id;
}

public void setId(int id) {
    this.id = id;
}

public double getValue() {
    return value;
}

public void setValue(double value) {
    this.value = value;
}

public Datetime getDatetime() {
    return datetime;
}

public void setDatetime(Datetime datetime) {
    this.datetime = datetime;
}

@com.google.gson.annotations.SerializedName("dateTime")
public Datetime datetime;

public static class Chronology {
    @com.google.gson.annotations.SerializedName("id")
    public String id;
    @com.google.gson.annotations.SerializedName("calendarType")
    public String calendartype;

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getCalendartype() {
        return calendartype;
    }

    public void setCalendartype(String calendartype) {
        this.calendartype = calendartype;
    }
}

public static class Datetime {
    @com.google.gson.annotations.SerializedName("hour")
    public int hour;
    @com.google.gson.annotations.SerializedName("minute")
    public int minute;
    @com.google.gson.annotations.SerializedName("second")
    public int second;
    @com.google.gson.annotations.SerializedName("nano")
    public int nano;
    @com.google.gson.annotations.SerializedName("dayOfYear")
    public int dayofyear;
    @com.google.gson.annotations.SerializedName("dayOfWeek")
    public String dayofweek;
    @com.google.gson.annotations.SerializedName("month")
    public String month;
    @com.google.gson.annotations.SerializedName("dayOfMonth")
    public int dayofmonth;
    @com.google.gson.annotations.SerializedName("year")
    public int year;
    @com.google.gson.annotations.SerializedName("monthValue")
    public int monthvalue;
    @com.google.gson.annotations.SerializedName("chronology")
    public Chronology chronology;

    public int getHour() {
        return hour;
    }

    public void setHour(int hour) {
        this.hour = hour;
    }

    public int getMinute() {
        return minute;
    }

    public void setMinute(int minute) {
        this.minute = minute;
    }

    public int getSecond() {
        return second;
    }

    public void setSecond(int second) {
        this.second = second;
    }

    public int getNano() {
        return nano;
    }

    public void setNano(int nano) {
        this.nano = nano;
    }

    public int getDayofyear() {
        return dayofyear;
    }

    public void setDayofyear(int dayofyear) {
        this.dayofyear = dayofyear;
    }

    public String getDayofweek() {
        return dayofweek;
    }

    public void setDayofweek(String dayofweek) {
        this.dayofweek = dayofweek;
    }

    public String getMonth() {
        return month;
    }

    public void setMonth(String month) {
        this.month = month;
    }

    public int getDayofmonth() {
        return dayofmonth;
    }

    public void setDayofmonth(int dayofmonth) {
        this.dayofmonth = dayofmonth;
    }

    public int getYear() {
        return year;
    }

    public void setYear(int year) {
        this.year = year;
    }

    public int getMonthvalue() {
        return monthvalue;
    }

    public void setMonthvalue(int monthvalue) {
        this.monthvalue = monthvalue;
    }

    public Chronology getChronology() {
        return chronology;
    }

    public void setChronology(Chronology chronology) {
        this.chronology = chronology;
    }
    }
    }

然后，您可以将改造的响应分配给此类的对象，并使用设置器检索值。

于 2016-11-07T06:05:25.697 回答