我正在尝试使用 AkkaConsistentHashingRoutingLogic
来保证具有相同密钥的消息被路由到同一个 Actor。重要的是,具有相同键的消息按 FIFO 顺序处理。不同key的消息可以路由到不同的Actor,自由并行处理。我没有在分布式模式下使用 Akka。
这些消息实际上是从 RabbitMQ 代理读取的 JSON 消息,因此我的 Master Actor 接收到 AMQP 消息并使用路由键作为消息键。相同的密钥也在消息本身中。Actor 是 Spring 应用程序的一部分。
我的主演员看起来像这样:
@Named("MessageHandlerMaster")
@Scope(ConfigurableBeanFactory.SCOPE_PROTOTYPE)
public class MessageHandlerMaster extends UntypedActor {
private static final Logger log = LoggerFactory.getLogger(MessageHandlerMaster.class);
private Router router;
@Autowired
public MessageHandlerMaster(final SpringProps springProps) {
List<Routee> routees = Stream.generate(() -> {
ActorRef worker = getContext().actorOf(springProps.create(MessageHandlerWorker.class));
getContext().watch(worker);
return new ActorRefRoutee(worker);
}).limit(5) //todo: configurable number of workers
.collect(Collectors.toList());
router = new Router(new ConsistentHashingRoutingLogic(getContext().system()), routees);
}
public void onReceive(Object message) {
if (message instanceof Message) {
Message amqpMessage = (Message) message;
String encoding = getMessageEncoding(amqpMessage);
try {
String json = new String(amqpMessage.getBody(), encoding);
String routingKey = amqpMessage.getMessageProperties().getReceivedRoutingKey();
log.debug("Routing message based on routing key " + routingKey);
router.route(new ConsistentHashingRouter.ConsistentHashableEnvelope(json, routingKey), getSender());
} catch (UnsupportedEncodingException e) {
log.warn("Unknown content encoding sent in message! {}", encoding);
}
} else if (message instanceof Terminated) {
//if one of the routee's died, remove it and replace it
log.debug("Actor routee terminated!");
router.removeRoutee(((Terminated) message).actor());
ActorRef r = getContext().actorOf(Props.create(MessageHandlerWorker.class));
getContext().watch(r);
router = router.addRoutee(new ActorRefRoutee(r));
}
}
private static String getMessageEncoding(Message message) {
String encoding = message.getMessageProperties().getContentEncoding();
if ((encoding == null) || (encoding.equals(""))) {
encoding = "UTF-8";
}
return encoding;
}
}
我最初通过以下方式获得主人一次:
this.master = actorSystem.actorOf(springProps.create(MessageHandlerMaster.class), "master");
然后只需通过以下方式将消息提交给它:
master.tell(message, ActorRef.noSender());
但是,当我从我的工作人员打印日志时,onReceive()
我看到不同的调度程序线程有时被用于同一个键。
同样不清楚为什么有时相同的调度程序线程被用于 Master Actor 和 Worker Actor。这不应该是线程之间的异步消息传递吗?
16:45:13.359 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.359 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.360 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-9] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerMaster - Routing message based on routing key 10420186
16:45:13.361 [aggregator-akka.actor.default-dispatcher-10] DEBUG c.u.o.a.actors.MessageHandlerWorker - Handling message for 10420186
正如您在此处看到的,带有键 10420186 的 Worker 处理消息的调度程序线程有时是 9,有时是 10。Master actor 有时也使用这两个线程。
我如何确定它ConsistentHashingRoutingLogic
确实在工作并且同一个线程使用相同的密钥处理消息?我在路由器初始化中做错了什么吗?