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我正在使用 Swift 3 在 iOS 中创造某种财富之轮。我使用了一个带有 UIPickerView 的库,我自定义了视图,我使行数不胜数(因此用户认为他滚动浏览了无穷无尽的项目)。

唯一的问题是用户可以在命运之轮中缓慢滑动价格,所以基本上他可以选择任何他想要的价格。

我想防止这种情况发生的方法是,每当用户点击或滑动滚轮时,我会让 UIPickerView 旋转,并使用随机数来决定命运之轮的结果。

我知道如何向方向盘添加手势识别器,但我唯一不知道的是如何以编程方式启动 UIPickerView 旋转。

提前致谢!

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1 回答 1

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我想你正在寻找这个:

pick.selectRow(10, inComponent: 0, animated: true)

但是,如果您想查看我为您制作的完整示例。

class ViewController: UIViewController, UIPickerViewDataSource{

@IBOutlet var pick: UIPickerView!

var myArr = [Int]()

var myT = Timer()

override func viewDidLoad() {
    super.viewDidLoad()

    for element in 0...100 {

        myArr.append(element)
        }


    myT = Timer.scheduledTimer(timeInterval: 3, target: self, selector: #selector(ViewController.movePicker), userInfo: nil, repeats: true)



}



 //MARK: - move picker

func movePicker()  {


    let position = Int(arc4random_uniform(89) + 10)


    pick.selectRow(position, inComponent: 0, animated: true)
    pick.showsSelectionIndicator = true

    if position == 50 || position == 72 || position == 90 || position == 35  {

        myT.invalidate()

        let alert = UIAlertController(title: "You Won!!", message: "Congratulations!!!", preferredStyle: .alert)
        let buttonOK = UIAlertAction(title: "OK", style: UIAlertActionStyle.default, handler: nil)
        let playAgain = UIAlertAction(title: "Play Again!", style: .default, handler: { (action) in

            self.myT = Timer.scheduledTimer(timeInterval: 3, target: self, selector: #selector(ViewController.movePicker), userInfo: nil, repeats: true)
        })

        alert.addAction(buttonOK)
        alert.addAction(playAgain)

        present(alert, animated: true, completion: nil)



    }

}




 //MARK: - picker
func numberOfComponents(in pickerView: UIPickerView) -> Int {

    return 1

}

func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
    return myArr.count
}

func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
    return "\( myArr[row])"
}


}

我希望我对你有所帮助

于 2016-10-06T15:39:13.513 回答