我希望能够在单击动态链接时打开应用程序并打印参数(即使它没有发布)。
有没有办法做到这一点?
Yes! In fact, I go through this exact process in the getting started videoS (part 1), (part 2), which I recommend you check out if you haven't yet.
But, generally speaking, you can test the "Open my app if I have it installed" flow simply by clicking on a dynamic link. If your app is installed on the device, it should open up just fine; even if it's not a published app.
If you want to test the non-installed flow, this is pretty easy, too.
我遇到了同样的问题,在花了很多时间试图找到解决方案后,并按照 Todd Kerpelman post解释的调试说明进行操作,我可以确定 firebase 在第一个应用程序启动时没有发送通用链接,并且已经发送具有以下结构的方案 URL:
[bundle_id]://google/link/?deep_link_id=[firebase_universal_link]
dynamicLinkFromCustomSchemeURL
确定之后,我在 Firesabe SDK 中找到了该方法,我可以通过动态链接在第一个应用程序启动时解决我的问题。
/**
* @method dynamicLinkFromCustomSchemeURL:
* @abstract Get a Dynamic Link from a custom scheme URL. This method parses URLs with a custom
* scheme, for instance, "comgoogleapp://google/link?deep_link_id=abc123". It is suggested to
* call it inside your |UIApplicationDelegate|'s
* |application:openURL:sourceApplication:annotation| and |application:openURL:options:|
* methods.
* @param url Custom scheme URL.
* @return Dynamic Link object if the URL is valid and has link parameter, otherwise nil.
*/
- (nullable FIRDynamicLink *)dynamicLinkFromCustomSchemeURL:(NSURL *)url
NS_SWIFT_NAME(dynamicLink(fromCustomSchemeURL:));
/**
* @method dynamicLinkFromUniversalLinkURL:completion:
* @abstract Get a Dynamic Link from a universal link URL. This method parses the universal link
* URLs, for instance,
* "https://example.page.link?link=https://www.google.com&ibi=com.google.app&ius=comgoogleapp".
* It is suggested to call it inside your |UIApplicationDelegate|'s
* |application:continueUserActivity:restorationHandler:| method.
* @param URL Custom scheme URL.
* @param completion A block that handles the outcome of attempting to get a Dynamic Link from a
* universal link URL.
*/
- (void)dynamicLinkFromUniversalLinkURL:(NSURL *)url
completion:(FIRDynamicLinkUniversalLinkHandler)completion
NS_SWIFT_NAME(dynamicLink(fromUniversalLink:completion:));
/**
* @method dynamicLinkFromUniversalLinkURL:
* @abstract Get a Dynamic Link from a universal link URL. This method parses universal link
* URLs, for instance,
* "https://example.page.link?link=https://www.google.com&ibi=com.google.app&ius=comgoogleapp".
* It is suggested to call it inside your |UIApplicationDelegate|'s
* |application:continueUserActivity:restorationHandler:| method.
* @param url Custom scheme URL.
* @return Dynamic Link object if the URL is valid and has link parameter, otherwise nil.
*/