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我们如何data-tag='to-do'在 OneNote API 中使用 OneNote 标签（如 ）进行搜索或过滤。我尝试使用提供运算符但没有成功。

我试过这样——

    $url = "https://www.onenote.com/api/v1.0/me/notes";
    //$url .= "/pages?search=hello";
    $url .= "/pages?filter=data-tag eq 'to-do'";

我想搜索 data-tag，然后从包含 data-tag='to-do' 的 OneNote 页面中提取数据。

任何帮助表示赞赏并提前感谢。

4

2 回答 2

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遗憾的是 OneNote API 还不支持它，所以我编写了我的自定义解析器，它从页面内容中提取带有数据标签的笔记。这里是： 

public class OneNoteParser
    {
        static public List<Note> ExtractTaggedNotes(string pageContent, string tag = "*")
        {
            List<Note> allNotes = new List<Note>();

            string[] dataTagString = { "data-tag=\""};

            string[] dirtyNotes = pageContent.Split(dataTagString, StringSplitOptions.RemoveEmptyEntries);

            //First one in this array can be dropped as it doesn't contain todo
            for (int i = 1; i < dirtyNotes.Length; i  )
            {
                string curStr = dirtyNotes[i];
                Note curNote = new Note();

                // Firstly we need to extract all the tags from it (sample html: data-tag="to-do:completed,important" ....)
                string allTags = curStr.Substring(0,curStr.IndexOf("\""));

                curNote.Tags = new List<string>(allTags.Split(','));

                // Now we have to jump to the next ">" symbol and start finding the text after it
                curStr = curStr.Substring(curStr.IndexOf(">"));

                int depth = 1;
                bool addAllowed = false;

                for (int j = 0; j < curStr.Length - 1; j  )
                {
                    // Finding next tag opener "<" symbol
                    if (curStr[j] == '<')
                    {
                        addAllowed = false;

                        // Checking if it is not "</" closer
                        if (curStr[j   1] == '/')
                        {
                            // Means this is a tag closer. Decreasing depth
                            depth--;
                        }
                        else
                        {
                            // Means this is an tag opener. Increasing depth
                            depth  ;
                        }
                    }
                    else if (curStr[j] == '>')
                    {
                        addAllowed = true;

                        if (j > 0 && curStr[j - 1] == '/')
                        {
                            // Means this is a tag closer. Decreasing depth
                            depth--;
                        }
                    }
                    else
                    {
                        if (depth < 1)
                        {
                            // Found end of the tag. Saving index and exiting for loop
                            break;
                        }

                        if (addAllowed)
                            curNote.Text  = curStr[j]; // Appending letter to string
                    }
                }

                // Filtering by tag and adding to final list
                if (tag == "*" || curNote.Tags.Any(str => str.Contains(tag)))//curNote.Tags.Contains(tag, StringComparer.CurrentCultureIgnoreCase))
                        allNotes.Add(curNote);

            }
            return allNotes;
        }
    }

这是课程Note 

   public class Note
    {
        public string Text;
        public List<string> Tags;
        public Note()
        {
            Tags = new List<string>();
        }
    }

要提取 todo-s，只需调用此函数： 

OneNoteParser.ExtractTaggedNotes(pageContent, "to-do");

您也可以像这样提取其他标签： 

OneNoteParser.ExtractTaggedNotes(pageContent, "important");
OneNoteParser.ExtractTaggedNotes(pageContent, "highlight");
//...
于 2017-01-25T17:00:49.010 回答
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您必须浏览所有页面。

GET对于每个页面，您可以通过调用来检索其内容https://www.onenote.com/api/v1.0/me/notes/pages/%s/content?includeIds=true

从那里你得到一个可以解析的字符串。

我会建议你使用jsoup。

使用 jsoup 您可以编写（假设content包含您的页面内容）：

Document doc = Jsoup.parse(content);
Elements todos=doc.select("[data-tag^=\"to-do\"]");

for(Element todo:todos) {
    System.out.println(todo.ownText());
    }
于 2016-10-08T18:16:01.757 回答