scala - 在 Spark 数据框中爆炸嵌套结构

Question

我正在研究一个 Databricks 示例。数据框的架构如下所示：

> parquetDF.printSchema
root
|-- department: struct (nullable = true)
|    |-- id: string (nullable = true)
|    |-- name: string (nullable = true)
|-- employees: array (nullable = true)
|    |-- element: struct (containsNull = true)
|    |    |-- firstName: string (nullable = true)
|    |    |-- lastName: string (nullable = true)
|    |    |-- email: string (nullable = true)
|    |    |-- salary: integer (nullable = true)

在示例中，他们展示了如何将员工列分解为 4 个附加列：

val explodeDF = parquetDF.explode($"employees") { 
case Row(employee: Seq[Row]) => employee.map{ employee =>
  val firstName = employee(0).asInstanceOf[String]
  val lastName = employee(1).asInstanceOf[String]
  val email = employee(2).asInstanceOf[String]
  val salary = employee(3).asInstanceOf[Int]
  Employee(firstName, lastName, email, salary)
 }
}.cache()
display(explodeDF)

我将如何对部门列做类似的事情（即向数据框中添加两个名为“id”和“name”的附加列）？这些方法并不完全相同，我只能弄清楚如何使用以下方法创建一个全新的数据框：

val explodeDF = parquetDF.select("department.id","department.name")
display(explodeDF)

如果我尝试：

val explodeDF = parquetDF.explode($"department") { 
  case Row(dept: Seq[String]) => dept.map{dept => 
  val id = dept(0) 
  val name = dept(1)
  } 
}.cache()
display(explodeDF)

我收到警告和错误：

<console>:38: warning: non-variable type argument String in type pattern Seq[String] is unchecked since it is eliminated by erasure
            case Row(dept: Seq[String]) => dept.map{dept => 
                           ^
<console>:37: error: inferred type arguments [Unit] do not conform to    method explode's type parameter bounds [A <: Product]
  val explodeDF = parquetDF.explode($"department") { 
                                   ^

score 36 · Accepted Answer

在我看来，最优雅的解决方案是使用 select 运算符对 Struct 进行星号扩展，如下所示：

var explodedDf2 = explodedDf.select("department.*","*")

https://docs.databricks.com/spark/latest/spark-sql/complex-types.html

score 22 · Accepted Answer

你可以使用类似的东西：

var explodeDF = explodeDF.withColumn("id", explodeDF("department.id"))
explodeDeptDF = explodeDeptDF.withColumn("name", explodeDeptDF("department.name"))

你帮我解决了这些问题：

score 3 · Accepted Answer

这似乎可行（尽管可能不是最优雅的解决方案）。

var explodeDF2 = explodeDF.withColumn("id", explodeDF("department.id"))
explodeDF2 = explodeDF2.withColumn("name", explodeDF2("department.name"))

scala - 在 Spark 数据框中爆炸嵌套结构

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