1

我正在使用 jQuery 编写一个应用程序,当单击一个按钮时,会生成一个选择框并附加到一行。Whenever the select changes, it should trigger the change event, but using .on("change", function() {});isn't working:

代码:

<!DOCTYPE html>
<html>
    <head>
        <title>HTML5-Template</title>
        <meta http-equiv="content-type" content="text/html; charset=utf-8">
        <style type="text/css">
            html, body
            {
            }

            input,select {
                border: 1px solid #404048;
                padding: 4px;
            }
        </style>
        <script type="text/javascript" src="../JavaScript/JQuery/jquery-1.9.1.js"></script>
        <script type="text/javascript">
            $(document).ready(function() {
                $("#cmdCreateRow").click(function() {
                    var row = $("<div />")
                    .css("font", "normal 12px Verdana")
                    .css("padding", "8px")
                    .css("display", "inline-block")
                    .css("background", "#F0F0F8")
                    .css("border", "1px solid #A0A0A8")
                    .css("margin", "2px");

                    var types = [
                        "Local", 
                        "Remote",
                        "(Custom)"
                    ];

                    var type = $("<select />").attr("class", "member-type");
                    for(var i in types) {
                        type.append($("<option />").val(types[i]).text(types[i]));
                    };

                    row.append(type);

                    $("#Container").append(row).append($("<br />"));
                });

                $(".member-type").on("change", function() {
                    alert("changed");
                });
            });
        </script>
    </head>
    <body>
        <input type="button" id="cmdCreateRow" value="Create Row" />
        <div id="Container">
        </div>
    </body>
</html>

知道我做错了什么吗?

4

2 回答 2

9

$(".member-type")你进行绑定时是空的,你什么也没做。

改变

$(".member-type").on("change", function() {
       alert("changed");
});

$(document).on("change", ".member-type", function() {
         alert("changed");
});

或者这是因为 #Container 元素是静态的:

$("#Container").on("change", ".member-type", function() {
         alert("changed");
});
于 2013-05-30T13:34:56.607 回答
1

试试这个:

$(document).on("change", ".member-type", function() {
    //Code
});

这是 jQuery 中“live”的替代品,请参阅:http ://api.jquery.com/live/

--

常规的“on”方法只适用于 DOM 中已经存在的元素。

于 2013-05-30T13:36:01.970 回答