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如何通过 FormEncode 验证用逗号分隔的单词?

像这样的东西:

"foo1, foo2, foo3" -> ["foo1", "foo2", "foo3"]
4

2 回答 2

1

您可能需要一个自定义验证器。这是一个简单的例子:

import formencode

class CommaSepList(formencode.validators.FancyValidator):

    def _to_python(self, value, state):
        return value.split(",")

    def validate_python(self, value, state):
        for elem in value:
            if elem == "": 
                raise formencode.Invalid("an element of the list is empty", value, state) 

>>> CommaSepList.to_python("1,2,3")
['1', '2', '3']
>>> CommaSepList.to_python("1,,")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python2.5/site-packages/FormEncode-1.2.3dev-py2.5.egg/formencode/api.py", line 416, in to_python
    vp(value, state)
  File "myValidator.py", line 17, in validate_python
    raise formencode.Invalid("an element of the list is empty", value, state)

当然,您需要添加特定于您的用例的验证。

于 2010-10-13T14:33:02.903 回答
0

假设每个单词由逗号和空格 ( ', ') 分隔:

>>> x = "foo1, bar2, foo3"
>>> x.split(', ')
['foo1', 'bar2', 'foo3']

然后将该列表传递给 FormEncode 并让它做任何你需要做的事情。

于 2010-10-13T14:15:29.793 回答