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我正在为 iPad 开发一个简单的写作应用程序。

我正在尝试计算光标在UITextView. 我花了几个星期来设计这个,但我还是想不通。

在 stackoverflow 中,Tony 编写了一个很好的算法来找到光标的像素位置。

UITextView 中光标的像素位置

我通过一些修改实现了这一点,它几乎可以提供正确的光标像素位置。但是,它仅适用于英文字母。

如果行尾有中文或日文字符UITextView,即使中文字符之间没有空格,也执行字符换行,而不是自动换行。我认为托尼的算法在UITextView仅执行自动换行(使用英文字母)时有效。

有没有其他方法可以找到光标的像素位置UITextView

或者有没有办法确定一个特定的字符是像汉字一样遵循字符换行还是像英语一样进行自动换行?

添加:

这是我基于托尼算法的实现。我把一个UITextView放在横向模式,所以它的宽度是 1024,我使用了自定义字体,大小为 21。你应该适当sizeOfContentWidth地改变sizeOfContentLinesizeOfContentWidth小于实际宽度,sizeOfContentLine大于实际字体大小(行高>字体大小)。

对不起,混乱的代码和评论!还有一些小错误,如果在行尾输入中文字符会给出错误的位置(没有自动换行)。

#define sizeOfContentWidth 1010
#define sizeOfContentHeight 1000
#define sizeOfContentLine 25

    // Stores the original position of the cursor
NSRange originalPosition = textView.selectedRange;    

// Computes textView's origin
CGPoint origin = textView.frame.origin;

// Checks whether a character right to the current cursor is a non-space character
unichar c = ' ';

if(textView.selectedRange.location != [textView.text length])
    c = [textView.text characterAtIndex:textView.selectedRange.location];

// If it's a non-space or newline character, then the current cursor moves to the end of that word
if(c != 32 && c != 10){
    NSRange delimiter = [textView.text rangeOfCharacterFromSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]
                                                       options:NSLiteralSearch
                                                         range:NSMakeRange(textView.selectedRange.location, [textView.text length] - textView.selectedRange.location)];

    if(delimiter.location == NSNotFound){
        delimiter.location = [textView.text length];
    }

    textView.selectedRange = delimiter;
}

// Deviation between the original cursor location and moved location
int deviationLocation = textView.selectedRange .location - originalPosition.location;

// Substrings the part before the cursor position
NSString* head = [textView.text substringToIndex:textView.selectedRange.location];

// Gets the size of this part
CGSize initialSize = [head sizeWithFont:textView.font constrainedToSize:CGSizeMake(sizeOfContentWidth, sizeOfContentHeight)];

// Gets the length of the head
NSUInteger startOfLine = [head length];

// The first line
BOOL isFirstLine = NO;

if(initialSize.height / sizeOfContentLine == 1){
    isFirstLine = YES;
}

while (startOfLine > 0 && isFirstLine == NO) {
    // 1. Adjusts startOfLine to the beginning of the first word before startOfLine
    NSRange delimiter = [head rangeOfCharacterFromSet:[NSCharacterSet whitespaceAndNewlineCharacterSet] options:NSBackwardsSearch range:NSMakeRange(0, startOfLine)];

    // Updates startsOfLine
    startOfLine = delimiter.location;

    // 2. Check if drawing the substring of head up to startOfLine causes a reduction in height compared to initialSize. 
    NSString *tempHead = [head substringToIndex:startOfLine];

    // Gets the size of this temp head
    CGSize tempHeadSize = [tempHead sizeWithFont:textView.font constrainedToSize:CGSizeMake(sizeOfContentWidth, sizeOfContentHeight)];

    // Counts the line of the original
    int beforeLine = initialSize.height / sizeOfContentLine;

    // Counts the line of the one after processing
    int afterLine = tempHeadSize.height / sizeOfContentLine;

    // 3. If so, then you've identified the start of the line containing the cursor, otherwise keep going.
    if(beforeLine != afterLine)
        break;
}

// Substrings the part after the cursor position
NSString* tail;

if(isFirstLine == NO)
    tail = [head substringFromIndex:(startOfLine + deviationLocation)];
else {
    tail = [head substringToIndex:(startOfLine - deviationLocation)];
}

// Gets the size of this part
CGSize lineSize = [tail sizeWithFont:textView.font forWidth:sizeOfContentWidth lineBreakMode:UILineBreakModeWordWrap];

// Gets the cursor position in coordinate
CGPoint cursor = origin;    
cursor.x += lineSize.width;
cursor.y += initialSize.height - lineSize.height;

// Back to the original position
textView.selectedRange = originalPosition;

// Debug
printf("x: %f,   y: %f\n", cursor.x, cursor.y);
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2 回答 2

2

如果你只针对 IOS7,你可以使用 UITextView 方法:

- (CGRect)caretRectForPosition:(UITextPosition *)position;

短样本:

NSRange range; // target location in text that you should get from somewhere, e.g. textview.selectedRange
UITextView textview; // the text view

UITextPosition *start = [textview positionFromPosition:textview.beginningOfDocument offset:range.location];
CGRect caretRect = [self caretRectForPosition:start]; // caret rect in UITextView
于 2013-11-11T19:15:37.250 回答
0

这可能效率很低,但是您能否采用与您发布的代码相同的基本原理并采用光标所在的文本行,并遍历每个单独的字符并[NSString sizeWithFont:forWidth:lineBreakMode:]计算每个字符的宽度,您可以添加所有那些适合你的 x 职位?只是一个想法,但可能有助于解决自动换行问题。

于 2011-06-29T21:20:10.877 回答