我写了一个很小的c程序。GCC 4.8.5 20150623 (Red Hat 4.8.5-4) 成功编译的代码-std=c99
,但给了我一个警告。我无法处理警告,我什至不知道它有什么问题。代码在这里:
#include <stdio.h>
#define COLS 4
int SumOf2DArray(const int array[][COLS], int rows);
int SumOfArray(const int array[], int element_number);
int main(void) {
int sum_of_array0, sum_of_2d_array, sum_of_array1;
int *array, (*dimensions)[COLS];
array = (int [2]){10, 20};
dimensions = (int [2][COLS]){{1, 2, 3, -9}, {4, 5, 6, -8}};
sum_of_array0 = SumOfArray(array, 2);
sum_of_2d_array = SumOf2DArray(dimensions, 2);
sum_of_array1 = SumOfArray((int []){4, 4, 4, 5, 5, 5}, 6);
printf("sum_of_array0 = %d \t sum_of_2d_array = %d \t sum_of_array1 = %d\n",
sum_of_array0, sum_of_2d_array, sum_of_array1);
return 0;
}
int SumOf2DArray(const int array[][COLS], int rows) {
int sum_of_2d_array = 0;
for (int rows_i = 0; rows_i < rows; rows_i++) {
for (int cols_i = 0; cols_i < COLS; cols_i++) {
sum_of_2d_array += array[rows_i][cols_i];
}
}
return sum_of_2d_array;
}
int SumOfArray(const int array[], int element_number) {
int sum_of_array = 0;
for (int i = 0; i < element_number; i++) {
sum_of_array += array[i];
}
return sum_of_array;
}
警告在这里:
chapter10_compound_literals.c: In function ‘main’:
chapter10_compound_literals.c:25:3: warning: passing argument 1 of ‘SumOf2DArray’ from incompatible pointer type [enabled by default]
sum_of_2d_array = SumOf2DArray(dimensions, 2);
^
chapter10_compound_literals.c:15:5: note: expected ‘const int (*)[4]’ but argument is of type ‘int (*)[4]’
int SumOf2DArray(const int array[][COLS], int rows);
现在,我假设我有一个二维数组:int array[2][3] = {{1, 2, 3}, {3, 4, 5}}
,并且我有一个函数:int SumOf2DArray(const int array[][3], int rows)
。
上面代码中的方式是使用指针(int (*pointer)[3] = array
),但得到一个警告,我试图array
直接使用传递参数,但同样的警告。
如何将数组传递给函数?