我不知道如何在地图中设置每个神经元的定位。这是一个神经元和映射：
typedef struct _neuron
{
mfcc_frame *frames;
char *name;
double *weights;
int num_weights;
int x;
int y;
} neuron;
typedef struct _map
{
neuron *lattice;
int latice_size;
double mapRadius;
int sideX, sideY;
int scale;
} map;
如果我有多个相等的单词，如何计算模式输入（单词）和我的神经元之间的距离。
我不确定重量。我将权重定义为一个单词的 mfcc 特征的数量，但是在训练中我需要根据神经元之间的距离来更新这个权重。我正在使用神经元之间的欧几里得距离。但问题是如何更新权重。这里是init map和神经元的代码
void init_neuron(neuron *n, int x, int y, mfcc_frame *mfcc_frames, unsigned int n_frames, char *name){
double r;
register int i, j;
n->frames = mfcc_frames;
n->num_weights = n_frames;
n->x = x;
n->y = y;
n->name = malloc (strlen(name) * sizeof(char));
strcpy(n->name, name);
n->weights= malloc (n_frames * sizeof (double));
for(i = 0; i < n_frames; i++)
for(j = 0; j < N_MFCC; j++)
n->weights[i] = mfcc_frames[i].features[j];
printf("%s lattice %d, %d\n", n->name, n->x, n->y);
}
初始化地图：
map* init_map(int sideX, int sideY, int scale){
register int i, x, y;
char *name = NULL;
void **word_adresses;
unsigned int n = 0, count = 0;
int aux = 0;
word *words = malloc(sizeof(word));
map *_map = malloc(sizeof(map));
_map->latice_size = sideX * sideY;
_map->sideX = sideX;
_map->sideY = sideY;
_map->scale = scale;
_map->lattice = malloc(_map->latice_size * sizeof(neuron));
mt_seed ();
if ((n = get_list(words))){
word_adresses = malloc(n * sizeof(void *));
while (words != NULL){
x = mt_rand() %sideX;
y = mt_rand() %sideY;
printf("y : %d x: %d\n", y, x);
init_neuron(_map->lattice + y * sideX + x, x, y, words->frames, words->n, words->name);
word_adresses[count++] = words;
words = words->next;
}
for (i = 0; i < count; i++)
free(word_adresses[i]);
free(word_adresses);
aux++;
}
return _map;
}