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我们正在使用 Photon 引擎制作随机配对游戏。我们希望在一定时间内将玩家与不同的用户进行匹配。如果 PlayerA 和 PlayerB 一起玩，他们在 30 分钟内不能再玩。做这种系统的最佳方法是什么？

我们尝试了一些算法，但它并不适合。

public override void OnJoinedRoom()
{
    if(PhotonNetwork.isMasterClient) 
        StartCoroutine("StartWaiting");

    theSameGame = false;

    var photonPlayer =  PhotonNetwork.Instantiate("PhotonPlayerKO", Vector3.zero, Quaternion.identity, 0) as GameObject;
    photonPlayer.name = "Local Player";


    if(PhotonNetwork.playerList.Count() > 1 && !PhotonNetwork.isMasterClient)
        photonViewOfManager.RPC("MyNameIs", PhotonTargets.Others, PlayerInfos.thePlayersName);
    //Sending player name to other player to check whether this name is playable or not ?

    if(!PhotonNetwork.isMasterClient)
        StartCoroutine("CheckError");



}

它可以工作，但有一些缺点，例如耗时 vs. 有更好的解决方案的想法吗？

4

1 回答 1

2

解决方案可以在这里找到：文档

您需要使用SQL Lobby Type：

创建房间：

    RoomOptions roomOptions = new RoomOptions();
    roomOptions.MaxPlayers = expectedMaxPlayers;
   // in this example, C0 might be 0 or 1 for the two (fictional) game modes
    roomOptions.customRoomProperties = new ExitGames.Client.Photon.Hashtable() { { "C0", 1 } };
    roomOptions.customRoomPropertiesForLobby = new string[] { "C0" }; // this makes "C0" available in the lobby
    // let's create this room in SqlLobby "myLobby" explicitly
    TypedLobby sqlLobby = new TypedLobby("myLobby", LobbyType.SqlLobby);
    lbClient.OpCreateRoom(roomName, roomOptions, sqlLobby);

加盟房：

TypedLobby sqlLobby = new TypedLobby("myLobby", LobbyType.SqlLobby);    // same as above
string sqlLobbyFilter = "C0 = 0";   // find a game with mode 0
lbClient.OpJoinRandomRoom(null, expectedMaxPlayers, matchmakingMode, sqlLobby, sqlLobbyFilter);
// more filter variations:
// "C0 = 1 AND C2 > 50"
// "C5 = \"Map2\" AND C2 > 10 AND C2 < 20"

在您的情况下，您只需将 C0 替换为被阻止的玩家列表，并在每次新用户玩游戏时更新此列表，并在 30 分钟后将其从列表中删除。

如果您将面临其他一些问题，请告诉我们。

于 2016-08-10T23:03:44.307 回答