我正在使用 Apache Spark 2.0 并case class
为DetaSet
. 当我尝试根据如何在数据集中存储自定义对象来定义自定义编码器时?,因为java.time.LocalDate
我得到了以下异常:
java.lang.UnsupportedOperationException: No Encoder found for java.time.LocalDate
- field (class: "java.time.LocalDate", name: "callDate")
- root class: "FireService"
at org.apache.spark.sql.catalyst.ScalaReflection$.org$apache$spark$sql$catalyst$ScalaReflection$$serializerFor(ScalaReflection.scala:598)
at org.apache.spark.sql.catalyst.ScalaReflection$$anonfun$9.apply(ScalaReflection.scala:592)
at org.apache.spark.sql.catalyst.ScalaReflection$$anonfun$9.apply(ScalaReflection.scala:583)
at scala.collection.TraversableLike$$anonfun$flatMap$1.apply(TraversableLike.scala:241)
at scala.collection.TraversableLike$$anonfun$flatMap$1.apply(TraversableLike.scala:241)
at scala.collection.immutable.List.foreach(List.scala:381)
at scala.collection.TraversableLike$class.flatMap(TraversableLike.scala:241)
............
以下是代码:
case class FireService(callNumber: String, callDate: java.time.LocalDate)
implicit val localDateEncoder: org.apache.spark.sql.Encoder[java.time.LocalDate] = org.apache.spark.sql.Encoders.kryo[java.time.LocalDate]
val fireServiceDf = df.map(row => {
val dateFormatter = java.time.format.DateTimeFormatter.ofPattern("MM/dd /yyyy")
FireService(row.getAs[String](0), java.time.LocalDate.parse(row.getAs[String](4), dateFormatter))
})
我们如何为 spark 定义第三方 api 的编码器?
更新
当我为整个案例类创建编码器时,df.map..
将对象映射为二进制,如下所示:
implicit val fireServiceEncoder: org.apache.spark.sql.Encoder[FireService] = org.apache.spark.sql.Encoders.kryo[FireService]
val fireServiceDf = df.map(row => {
val dateFormatter = java.time.format.DateTimeFormatter.ofPattern("MM/dd/yyyy")
FireService(row.getAs[String](0), java.time.LocalDate.parse(row.getAs[String](4), dateFormatter))
})
fireServiceDf: org.apache.spark.sql.Dataset[FireService] = [value: binary]
我期待 FireService 的地图,但返回地图的二进制文件。