1

我目前正在尝试使用 Java 和库 net.oauth 向 Mendeley 进行身份验证。我的目标是从 Mendeley 检索读者数据,将它们添加到我们的学术文档数据库中。

不幸的是,我目前收到 401 和以下异常:

net.oauth.client.OAuthClient.invoke(OAuthClient.java:246) 处的 net.oauth.OAuthProblemException net.oauth.client.OAuthClient.invoke(OAuthClient.java:143) 处的 net.oauth.client.OAuthClient.getRequestToken( OAuthClient.java:101) 在 net.oauth.client.OAuthClient.getRequestToken(OAuthClient.java:77) 在 net.oauth.client.OAuthClient.getRequestToken(OAuthClient.java:116) 在 org.mrdlib.mendeleyCrawler.mendeleyConnection.defaultClient (mendeleyConnection.java:82) 在 org.mrdlib.mendeleyCrawler.mendeleyConnection.getReadership(mendeleyConnection.java:124) 在 org.mrdlib.mendeleyCrawler.mendeleyConnection.main(mendeleyConnection.java:190) 在 sun.reflect.NativeMethodAccessorImpl.invoke0(本机方法)在 sun.reflect.NativeMethodAccessorImpl。invoke(NativeMethodAccessorImpl.java:62) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:497) at org.eclipse.jdt.internal.jarinjarloader .JarRsrcLoader.main(JarRsrcLoader.java:58)

我使用以下代码:

public class mendeleyConnection {

private OAuthAccessor client;
private String access_token;
private String request_token;
private DBConnection con;

public mendeleyConnection() {
    con = new DBConnection();
}

public String convertToAccessToken(String request_token) {
    ArrayList<Map.Entry<String, String>> params = new ArrayList<Map.Entry<String, String>>();
    OAuthClient oclient = new OAuthClient(new HttpClient4());
    OAuthAccessor accessor = client;
    params.add(new OAuth.Parameter("oauth_token", request_token));
    try {
        OAuthMessage omessage = oclient.invoke(accessor, "POST", accessor.consumer.serviceProvider.accessTokenURL,
                params);
        return omessage.getParameter("oauth_token");
    } catch (OAuthProblemException e) {
        e.printStackTrace();
        return "";
    } catch (Exception ioe) {
        ioe.printStackTrace();
        return "";
    }
}

public OAuthAccessor defaultClient() {
    String callbackUrl = "some fallback url";
    String consumerKey = "the id of the mendeley application";
    String consumerSecret = "a generated secret";
    String reqUrl = "https://www.mendeley.com/oauth/request_token/";
    String authzUrl = "https://api-oauth2.mendeley.com/oauth/authorize/";
    String accessUrl = "https://www.mendeley.com/oauth/access_token/";
    OAuthServiceProvider provider = new OAuthServiceProvider(reqUrl, authzUrl, accessUrl);
    OAuthConsumer consumer = new OAuthConsumer(callbackUrl, consumerKey, consumerSecret, provider);
    OAuthAccessor accessor = new OAuthAccessor(consumer);

    OAuthClient oaclient = new OAuthClient(new HttpClient4());

    try {
        oaclient.getRequestToken(accessor);
        request_token = accessor.requestToken;
    } catch (OAuthProblemException e) {
        e.printStackTrace();
        System.out.println(e.getHttpStatusCode());
    } catch (Exception e) {
        e.printStackTrace();
    }
    return accessor;
}

public HashMap<String, Readership> getReadership() {
    HashMap<String, Readership> map = new HashMap<String, Readership>();
    List<String> documentTitles = new ArrayList<>();
    Readership readership = null;
    String mendeleyId = null;
    int score = 0;
    HttpPost httppost = new HttpPost();
    URL url = null;
    String nullFragment = null;
    JSONObject jsonObject = null;

    documentTitles = con.getAllDocumentTitles();

    for (int i = 0; i < documentTitles.size(); i++) {
        String current = documentTitles.get(i);

        HttpClient httpclient = HttpClientBuilder.create().build();
        String urlString = "https://api.mendeley.com/catalog?title=" + current;

        client = defaultClient();
        access_token = convertToAccessToken(client.requestToken);

        try {
            url = new URL(urlString);
            URI uri = new URI(url.getProtocol(), url.getHost(), url.getPath(), url.getQuery(), nullFragment);
            httppost = new HttpPost(uri);
            httppost.addHeader("Authorization", "Bearer " + client.requestToken);


            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("action", "getjson"));

            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            String data = EntityUtils.toString(response.getEntity());

            jsonObject = (JSONObject) JSONValue.parse(data);
            mendeleyId = (String) jsonObject.get("id");
            score = (Integer) jsonObject.get("score");

        } catch (Exception e) {
            e.printStackTrace();
        }
       [...]
    }
    return map;
}

public static void main(String[] args) {
    mendeleyConnection mcon = new mendeleyConnection();
    mcon.getReadership();

}

}

异常被抛出

oaclient.getRequestToken(accessor);

由于我在 Http 请求和身份验证主题方面没有经验,因此我将不胜感激。我已经阅读了 Mendeley 的指南以及我在 Internet 上可以找到的所有示例。我也使用了 Get 请求,但这也不起作用。我更改了 Mendeley 的网址(因为在文档中它们有不同的网址,但不起作用)。我尝试了不同的例子。我什至尝试过 Google 的 API,但这纯粹是矫枉过正,我什至无法举一个例子。我目前猜测我的 url 可能仍然是错误的,因为我多次找到方法“defaultClient”的示例。或者也许 OAuth2 发生了变化?

谢谢您的帮助!

4

1 回答 1

0

您的网址一开始就不正确。

字符串 reqUrl = " https://www.mendeley.com/oauth/request_token/ ";

字符串 authzUrl = " https://api-oauth2.mendeley.com/oauth/authorize/ ";

字符串 accessUrl = " https://www.mendeley.com/oauth/access_token/ ";

以下是来自我们的开发人员门户的授权代码流文档,您可能会发现它很有用 - http://dev.mendeley.com/reference/topics/authorization_auth_code.html

于 2016-08-02T11:00:46.800 回答