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我想通过搜索输入从数据库中搜索我的数据，一切正常，但我找不到为什么这段代码不起作用。当我在输入框中输入搜索数据时，任何事情都完成了。请帮助

我的控制器：AdUnitsController

 class AdUnitsController extends AppController

{

public function index()
{

    $query = $this->_getData();
    $this->set('adUnits', $this->paginate($query));

    $this->paginate = [
        'contain' => ['Networks', 'Games', 'AdTypes']
    ];

    $adUnits = $this->paginate($this->AdUnits);

    $this->set(compact('adUnits'));
    $this->set('_serialize', ['adUnits']);

}

public function _getData()
{
    if (!empty($this->request->data['search'])) {
        $search = $this->request->data['search'];
        $query = $this->AdUnits->find('All')->where([
            'OR' => [
                ['name LIKE' => '%' . $search . '%'],
            ],
        ]);
    }
    else{
        $query = $this->AdUnits->find('All');
    }
    return $query;
}

我的视图 index.ctp:

        <label> Search</label>
        <?php echo $this->Form->create('AdUnits',array('id' => 'site-search','url'=>array('action'=>'index')));?>
        <div>
            <?php echo $this->Form->input('search',array('class' => 'form-control', 'label' =>false, 'placeholder' => 'Type Network')); ?>
        </div>

        <div> <button type="submit"> Search</button>

            <?php echo $this->Form->end();?>

那里搜索不起作用。请帮助

4

2 回答 2

1

首先简化您的代码：您正在无缘无故地进行两次分页

public function index()
{
    $this->paginate = [
        'contain' => ['Networks', 'Games', 'AdTypes']
    ];
    $query = $this->_getData();
    $this->set('adUnits', $this->paginate($query));

}

如果您仍然遇到问题，您的查询可能有错误。我的猜测是这些name列是模棱两可的，所以在你的find()电话中这样做

['AdUnits.name LIKE' => '%' . $search . '%']

作为旁注，我建议您阅读文档，特别是学习如何调试代码。

在_getData我看来，这些方法也应该移到模型或组件中。

于 2016-07-20T11:44:41.517 回答
0 
public function index()
{

    $query = $this->_getData();
    $this->set('adUnits', $this->paginate($query));

    $this->paginate = [
        'contain' => ['Networks', 'Games', 'AdTypes']
    ];

    $adUnits = $this->paginate($this->AdUnits);

    $this->set(compact('adUnits'));
    $this->set('_serialize', ['adUnits']);

}

用。。。来代替

    public function index()
{
    $this->paginate = [
        'contain' => ['Networks', 'Games', 'AdTypes']
    ];
    $query = $this->_getData();
    $this->set('adUnits', $this->paginate($query));

}
于 2016-07-20T11:14:57.293 回答