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我是 asp.net mvc 的新手，但我到处都在这个主题上进行了彻底的搜索。

我有一个名为 PictureViewModel 的 ViewModel 类，它是 EditorTemplate 视图继承自的类：<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl" %>

<div class="editor-label"><%: Html.LabelFor(m=>m.Name) %></div> 
<div class="editor-field"><%: Html.TextBox("form.Name") %></div> 

<div class="editor-label"><%: Html.LabelFor(m=>m.Description) %></div> 
<div class="editor-field"><%: Html.TextArea("form.Description") %></div> 

<% Html.RenderAction("SelectCategory", "Category"); %>

<div class="editor-label"><label for="thumbFile">Thumb</label></div> 
<div class="editor-field"><input id="thumbFile" name="thumbFile" type="file"/></div> 

<div class="editor-label"><label for="fullFile">Full</label></div> 
<div class="editor-field"><input id="fullFile" name="fullFile" type="file"/></div>

我也有文件字段和所有发布到自己的

<%@ Page Title="" Language="C#" MasterPageFile="/Views/Shared/Site_Table.Master"
 Inherits="System.Web.Mvc.ViewPage<MvcApplicationVelarPolya.Areas.Admin.Models.PictureViewModel>" %>

<asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">
    Create
</asp:Content>

<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">

    <h2>Create</h2>

    <%
  using (Html.BeginForm("create", "Pictures", FormMethod.Post, new {enctype="multipart/form-data"})) 
   {%> 

    <%: Html.EditorForModel() %>

    <input type="submit" name="Create" />

<% }%>

</asp:Content>

这是专门用于处理提交的代码：

    [HttpPost]
    public ActionResult Create([Bind(Prefix="form")] PictureViewModel pm)
    {
        try
        {
            var p = new PictureViewModel();
            UpdateModel(p, "",new[] {"Name", "Description"});
            ViewData["name"] = Request.Files[0].FileName;
            return View("New", p);
        }
        catch
        {
            return View();
        }
    }

添加前缀或将 FormCollection 与 UpdateModel 一起使用都无济于事。我将不胜感激任何帮助！安德鲁。

哦，是的，viewdata 正确地填充了文件名！

这也不起作用 [HttpPost] public ActionResult Create(FormCollection fc/ [Bind(Prefix="form")] PictureViewModel pm /) { try { var p = new PictureViewModel(); UpdateModel(p, "form",new[] {"Name", "Description"}); ViewData["name"] = Request.Files[0].FileName; // TODO: 在此处添加插入逻辑 return View("New", p); return RedirectToAction("索引"); } 捕捉 { 返回视图（）；} }

而这段代码

        foreach (var k in fc)
        {
            Debug.WriteLine(k.ToString());
        }

正在生产

form.Name
form.Description
CategoryID
Create
4

1 回答 1

1

在您的编辑器模板中，您应该使用强类型助手（TextBoxFor和TextAreaFor），您可以摆脱魔术字符串和前缀：

<div class="editor-label"><%: Html.LabelFor(m => m.Name) %></div> 
<div class="editor-field"><%: Html.TextBoxFor(m => m.Name) %></div> 

<div class="editor-label"><%: Html.LabelFor(m => m.Description) %></div> 
<div class="editor-field"><%: Html.TextAreaFor(m => m.Description) %></div> 

<% Html.RenderAction("SelectCategory", "Category"); %>

<div class="editor-label"><label for="thumbFile">Thumb</label></div> 
<div class="editor-field"><input id="thumbFile" name="thumbFile" type="file"/></div> 

<div class="editor-label"><label for="fullFile">Full</label></div> 
<div class="editor-field"><input id="fullFile" name="fullFile" type="file"/></div>

要处理上传的文件，您可以将它们添加为视图模型属性或操作参数：

public class PictureViewModel
{
    public string Name { get; set; }
    public string Description { get; set; }
    public HttpPostedFileBase ThumbFile { get; set; }
    public HttpPostedFileBase FullFile { get; set; }
}

...

[HttpPost]
public ActionResult Create(PictureViewModel pm)
{
    // Normally the pm variable should be fully 
    // initialized here from the POST request and you can use it directly
    // No need to call UpdateModel
    return View("New", pm);
}
于 2010-10-02T13:35:26.473 回答