2

我想知道我是否可以——以及如何——在这种情况下使用工厂模式？

我有以下课程...

public interface IStub<T> where T : class
{
    IEnumerable<T> CreateStubs();
}

public FooStub : IStub<Foo>
{
    public IEnumerable<Foo> CreateStubs() { ... }
}


public BarStub : IStub<Bar>
{
    public IEnumerable<Bar> CreateStubs() { ... }
}

.. ETC ...

我想知道是否可以通过工厂方法创建实例，例如...

// This ends up returning an enumerable of Stubs.
var stubs = StubsFactory.CreateStubs<Foo>();

这可能吗/我在正确的轨道上吗？

4

3 回答 3

0

像这样。如果实现和存根不在同一个程序集或命名空间中，请修改 Type.GetType 行。

class UberCoolFactory
{
      public static T CreateStubs<T>()  
      {
          string ns = typeof(T).Namespace;
          string name = typeof(T).Name;
          string assembly = typeof(T).Assembly.GetName().Name;
          Type type = Type.GetType(string.Format("{0}.{1}Stub, {2}", ns, name, assembly));
          return (T)Activator.CreateInstance(type);
      }
 }

选择：

 class FactoryTwo
 {
    /// <summary>
    /// Search through all loaded assemblies that exists in the current directory.
    /// </summary>
    /// <typeparam name="T"></typeparam>
    public static T CreateStub<T>() where T : class
    {
        string currentDir = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location);
        string wantedTypeName = typeof(T).Name + "Stub";

        List<Type> foundTypes = new List<Type>();
        foreach (var assembly in AppDomain.CurrentDomain.GetAssemblies())
        {
            if (!currentDir.Equals(Path.GetDirectoryName(assembly.Location)))
                continue;

            foreach (var type in assembly.GetTypes())
            {
                if (!type.Name.Equals(wantedTypeName))
                    continue;

                foundTypes.Add(type);
            }
        }


        if (!foundTypes.Any())
            return null;
        if (foundTypes.Count > 2)
            throw new AmbiguousMatchException("Found multiple stubs implementing '" + typeof(T).FullName + "'.");

        return (T) Activator.CreateInstance(foundTypes[0]);
    }
}

用法：

var instance = UberCoolFactory.CreateStubs<Foo>();
var instance2 = FactoryTwo.CreateStub<Foo>();
于 2010-10-02T05:27:32.537 回答
0

扩展 jgauffin 关于搜索目标类型的答案：

string targetType = "BlahStub";
IEnumerable<Type> result = 
        from assembly in AppDomain.CurrentDomain.GetAssemblies()
        where !String.Equals(Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location), assembly.Location, StringComparison.OrdinalIgnoreCase)
        from type in assembly.GetTypes()
        where String.Equals(type.Name, targetType, StringComparison.OrdinalIgnoreCase)
        select type;
于 2010-10-02T06:36:33.913 回答
0

工厂声明：

static class StubsFactory<TStub, TClass>
            where TStub : IStub<TClass>
            where TClass : class
{
    public static IEnumerable<TClass> CreateStubs()
    {
        return ((TStub)Activator.CreateInstance<TStub>()).CreateStubs();
    }
}

用法：

IEnumerable<Foo> q = StubsFactory<FooStub, Foo>.CreateStubs();

是你要找的吗？

于 2010-10-02T06:47:09.707 回答