此处测试图片：http: //images.plurk.com/tn_4134189_bf54fe8e270ce41240d534b5133884ee.gif
我尝试了在互联网上找到的几种解决方案，但没有有效的解决方案。
我正在使用以下代码段：
Url imageUrl = new Url("http://images.plurk.com/tn_4134189_bf54fe8e270ce41240d534b5133884ee.gif");
Bitmap image = BitmapFactory.decodeStream(imageUrl.openStream());
总是得到这个日志：
DEBUG/skia(1441): --- decoder->decode returned false
有什么帮助吗？谢谢。
编辑：
那些未能解码的图像也无法显示在WebView. 但可以查看是否在浏览器中打开。
我有同样的问题，部分由这个类修复：
static class FlushedInputStream extends FilterInputStream {
public FlushedInputStream(InputStream inputStream) {
super(inputStream);
}
@Override
public long skip(long n) throws IOException {
long totalBytesSkipped = 0L;
while (totalBytesSkipped < n) {
long bytesSkipped = in.skip(n - totalBytesSkipped);
if (bytesSkipped == 0L) {
int byte = read();
if (byte < 0) {
break; // we reached EOF
} else {
bytesSkipped = 1; // we read one byte
}
}
totalBytesSkipped += bytesSkipped;
}
return totalBytesSkipped;
}
}
和：
InputStream in = null;
try {
in = new java.net.URL(imageUrl).openStream();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
Bitmap image = BitmapFactory.decodeStream(new FlushedInputStream(in));
它在大多数情况下都有帮助，但这不是通用的解决方案。有关更多信息，请参阅此错误报告。
好运！
尝试将此作为临时解决方法：
首先添加以下类：
public static class PlurkInputStream extends FilterInputStream {
protected PlurkInputStream(InputStream in) {
super(in);
}
@Override
public int read(byte[] buffer, int offset, int count)
throws IOException {
int ret = super.read(buffer, offset, count);
for ( int i = 2; i < buffer.length; i++ ) {
if ( buffer[i - 2] == 0x2c && buffer[i - 1] == 0x05
&& buffer[i] == 0 ) {
buffer[i - 1] = 0;
}
}
return ret;
}
}
然后用 PlurkInputStream 包装你的原始流：
Bitmap bitmap = BitmapFactory.decodeStream(new PlurkInputStream(originalInputStream));
让我知道这是否对您有帮助。
编辑：
抱歉，请尝试以下版本：
for ( int i = 6; i < buffer.length - 4; i++ ) {
if ( buffer[i] == 0x2c ) {
if ( buffer[i + 2] == 0 && buffer[i + 1] > 0
&& buffer[i + 1] <= 48 ) {
buffer[i + 1] = 0;
}
if ( buffer[i + 4] == 0 && buffer[i + 3] > 0
&& buffer[i + 3] <= 48 ) {
buffer[i + 3] = 0;
}
}
}
请注意，这不是有效的代码，也不是完整/正确的解决方案。它适用于大多数情况，但不是全部。
我尝试了所有解决方案，但没有解决我的问题。经过一些测试，当互联网连接不稳定时，skia解码器失败的问题发生了很多。对我来说，强制重新下载图像解决了这个问题。
当图像尺寸较大时，该问题也更加突出。
使用循环最多需要我重试 2 次，并且图像将被正确下载。
Bitmap bmp = null;
int retries = 0;
while(bmp == null){
if (retries == 2){
break;
}
bmp = GetBmpFromURL(String imageURL);
Log.d(TAG,"Retry...");
retries++;
}
这应该有效：
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
connection.disconnect();
input.close();
myBitmap 包含您的图像。
这是由于 Android 中 InputStream 类中的一个错误。您可以在此处找到有效的解决方法和错误描述http://code.google.com/p/android/issues/detail?id=6066
试试这个：
HttpGet httpRequest = new HttpGet(url);
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = (HttpResponse) httpclient.execute(httpRequest);
HttpEntity entity = response.getEntity();
BufferedHttpEntity bufferedHttpEntity = new BufferedHttpEntity(entity);
InputStream is = bufferedHttpEntity.getContent();
Drawable d = Drawable.createFromStream(is, "");
//or bitmap
//Bitmap b = BitmapFactory.decodeStream(is);
出于内存原因，您必须像这样实现 BitmapFactory 选项：
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 4; // might try 8 also
主要的下载位图功能可能是这样的：
Bitmap downloadBitmap(String url) {
final HttpClient client = AndroidHttpClient.newInstance("Android");
final HttpGet getRequest = new HttpGet(url);
try {
HttpResponse response = client.execute(getRequest);
final int statusCode = response.getStatusLine().getStatusCode();
if (statusCode != HttpStatus.SC_OK) {
if(DEBUG)Log.w("ImageDownloader", "Error " + statusCode +
" while retrieving bitmap from " + url);
return null;
}
final HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream inputStream = null;
try {
inputStream = entity.getContent();
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 4; // might try 8 also
return BitmapFactory.decodeStream(new FlushedInputStream(inputStream),null,options);
} finally {
if (inputStream != null) {
inputStream.close();
}
entity.consumeContent();
}
}
} catch (IOException e) {
getRequest.abort();
if(DEBUG)Log.w(TAG, "I/O error while retrieving bitmap from " + url, e);
} catch (IllegalStateException e) {
getRequest.abort();
if(DEBUG)Log.w(TAG, "Incorrect URL: " + url);
} catch (Exception e) {
getRequest.abort();
if(DEBUG)Log.w(TAG, "Error while retrieving bitmap from " + url, e);
} finally {
if ((client instanceof AndroidHttpClient)) {
((AndroidHttpClient) client).close();
}
}
return null;
}
也许你必须像这样实现 AsyncTask： http ://android-developers.blogspot.com/2010/07/multithreading-for-performance.html
对我来说，问题在于图像的颜色类型：您的图像是 color=CYMK 而不是 RGB
