我已经在我的应用程序中实现了 MGTwitterEngine,它几乎可以完美运行。
当我将 UIViewController 推送到 Twitter 表单所在的位置时发生的第一件“奇怪”的事情,我在控制台中收到了这个:
This app was previously authorized for a Twitter account so you can press the second button to send a tweet now.
我应该隐藏登录表单还是您有什么建议?
发生的第二个“奇怪”的事情是当我按下“发送推文”按钮时它起作用并且消息发布在 Twitter 上。但是,我在方法中收到一条错误消息:
- (void) twitterXAuthConnectionDidFailWithError: (NSError *)error;
错误信息是:
Error Domain=NSURLErrorDomain Code=-1012 "The operation couldn’t be completed. (NSURLErrorDomain error -1012.)" UserInfo=0xde3edf0 {NSErrorFailingURLKey=https://api.twitter.com/oauth/access_token, NSErrorFailingURLStringKey=https://api.twitter.com/oauth/access_token, NSUnderlyingError=0xde430c0 "The operation couldn’t be completed. (kCFErrorDomainCFNetwork error -1012.)"}
我觉得很奇怪,因为 Twitter 消息已发布。但无论如何我都会收到该错误消息。
我查看了 Twitter 控制面板中的应用程序设置。访问类型为“读写”。
有谁熟悉这个问题?
我实现的委托方法是:
#pragma mark XAuthTwitterEngineDelegate methods
- (void) storeCachedTwitterXAuthAccessTokenString: (NSString *)tokenString forUsername:(NSString *)username
{
NSLog(@"Access token string returned: %@", tokenString);
[[NSUserDefaults standardUserDefaults] setObject:tokenString forKey:kCachedXAuthAccessTokenStringKey];
// Enable the send tweet button.
[loadingIndicator stopAnimating];
self.sendTweetButton.enabled = YES;
}
- (NSString *) cachedTwitterXAuthAccessTokenStringForUsername: (NSString *)username;
{
NSString *accessTokenString = [[NSUserDefaults standardUserDefaults] objectForKey:kCachedXAuthAccessTokenStringKey];
NSLog(@"About to return access token string: %@", accessTokenString);
return accessTokenString;
}
- (void) twitterXAuthConnectionDidFailWithError: (NSError *)error;
{
NSLog(@"Error: %@", error);
[loadingIndicator stopAnimating];
self.sendTweetButton.enabled = TRUE;
}
#pragma mark -
#pragma mark MGTwitterEngineDelegate methods
- (void)requestSucceeded:(NSString *)connectionIdentifier
{
UIAlertView *alert = [[UIAlertView alloc]
initWithTitle:@"Sent!"
message:@"The tweet is sent!"
delegate:self
cancelButtonTitle:nil
otherButtonTitles:@"Okay", nil];
[alert setTag:0];
[alert show];
[alert release];
[loadingIndicator stopAnimating];
self.sendTweetButton.enabled = TRUE;
}